How many significant figures has the number 0.00122950.

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
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**Question: How many significant figures does the number 0.00122950 have?**

**Explanation:**

To determine the number of significant figures in the number 0.00122950, it's essential to understand the rules for identifying significant figures:

1. **All non-zero digits are significant.**
2. **Any zeros between significant digits are significant.**
3. **Leading zeros (zeros before non-zero digits) are not significant.**
4. **Trailing zeros in a decimal number are significant.**

Applying these rules to the number 0.00122950:

- The leading zeros (0.00) are not significant.
- The digits 122950 are all significant because they include non-zero numbers and a trailing zero in the decimal part.

Thus, the number 0.00122950 has **6 significant figures**.
Transcribed Image Text:**Question: How many significant figures does the number 0.00122950 have?** **Explanation:** To determine the number of significant figures in the number 0.00122950, it's essential to understand the rules for identifying significant figures: 1. **All non-zero digits are significant.** 2. **Any zeros between significant digits are significant.** 3. **Leading zeros (zeros before non-zero digits) are not significant.** 4. **Trailing zeros in a decimal number are significant.** Applying these rules to the number 0.00122950: - The leading zeros (0.00) are not significant. - The digits 122950 are all significant because they include non-zero numbers and a trailing zero in the decimal part. Thus, the number 0.00122950 has **6 significant figures**.
**Problem Statement:**

Calculate the value of **the error** with one decimal place for:

\[ z = x \cdot y \]

where

\[ x = 25 \pm 8\% \]

and

\[ y = 35 \pm 2\% \]

Please enter the answer without +/- sign.
Transcribed Image Text:**Problem Statement:** Calculate the value of **the error** with one decimal place for: \[ z = x \cdot y \] where \[ x = 25 \pm 8\% \] and \[ y = 35 \pm 2\% \] Please enter the answer without +/- sign.
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