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Q = ([Li+]6 [Cl-]6)/([SmCl3]2) = (0.01006 * 0.01006)/(2.002) = 2.5 x 10-18 this calculation is wrong  its 2.5 X 10-25

Q = ([Li+]6 [Cl-]6)/([SmCl3]2) = (0.01006 * 0.01006)/(2.002) = 2.5 x 10-18 this calculation is wrong  its 2.5 X 10-25

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Q = ([Li+]6 [Cl-]6)/([SmCl3]2)

= (0.01006 * 0.01006)/(2.002) = 2.5 x 10-18

this calculation is wrong 

its 2.5 X 10-25

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Follow-up Question

i think it is 

The reaction quotient can be calculated from the reactants' and products' concentrations or partial pressures.

 2 SmCl3(aq) + 6 Li(aq) → 2 Sm(s) + 6 LiCl(aq)

 

At non-standard conditions, the concentrations are:

[SmCl3] = 2.00 M 

[Li] = 2.00M

[Sm] = 0 (solid) 

[LiCl] = 0.0100 M

 

The reaction quotient (Q) can be calculated as follows:

Q = {[LiCl]^6}/[Sm3+ ]^2[Cl3]^2 

= (0.0100)^6 /(2.00)^2 x (2.00)^2

= 6.25 x 10^-14

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Follow-up Question

can fix the other part of your solution then, I am double checking my calculations 

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