Copper metal reacts with dilute (10M) nitric acid by the following reaction. 3Cu(s)+8HNO3(aq)-à3Cu(NO3)2(aq)+NO(g)+4H2O(l) If this reaction took place rather than the first reaction, would your yield of CuCl be affected assuming you started with the same amount of copper metal? Explain your answer
1: Cu(s)+4HNO3(aq)à Cu(NO3)2(aq)+2NO2(g)+2H2O(l)
2: 2HNO3(aq)+Na2CO3(s)à H2O(l)+CO2(g)+2NaNO3(aq)
3: Cu(NO3)2(aq)+NaCO3(s)àCuCo3(s)+2NaNO3(aq)
4: CuCl2(aq)+Cu(s)à2CuCl(s)
Weight of Copper: 1.089g
Volume of Added Nitric Acid: 5.7 mL
Total weight of added Sodium Carbonate: 3.938 g
Weight of watch glass and filer paper: 52g
Weight of watch glass, filte rpaper, and precipitate: 53.945g
Experimental yield of CuCl: 1.945g
Theoretical yield of CuCl: 1.697 g
Percent yeild: 114.614 %
- Copper metal reacts with dilute (10M) nitric acid by the following reaction.
3Cu(s)+8HNO3(aq)-à3Cu(NO3)2(aq)+NO(g)+4H2O(l)
If this reaction took place rather than the first reaction, would your yield of CuCl be affected assuming you started with the same amount of copper metal? Explain your answer
- Could be use HCl to dissolve the copper metal instead of nitric acid in the first reaction? Explain your answer.
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