193r.) 2H (ag) +2e –H (g)0.00Snt (ag) + 2e= Sn²+ (aq)0.15Cu+ (ag) + e= Cu* (aq)0.16Cu+ (ag) + 2e Cu(s)0.34IO (ag) + H2 O(1) + 2e I (aq) + 20H (aq)0.49Cu" (ag) + e Cu(s)0.522(s) + 2e = 21 (aq)0.54Fe (aq) +e Fe+ (aq)0.77Hg, (aq) + 2e 2Hg(1)0.80Ag" (ag) +e Ag(s)0.80Hg (ag) + 2e Hg(1)0.85CIO (ag) + H2 0(1) + 2e Cl (ag) + 20H (aq)0.902H3²+ (ag) + 2e - Hg,+ (aq)0.90NO: (ag) + 4H (aq) + 3e NO(g) +2H2 O(1)0.96Br2 (1) + 2e 2Br (ag)1.07O2 (g) + 4H (ag) + 4e 2H,0(1)1.23Cr2 0,2 (ag) + 14H (ag) + 6e 2Cr (aq) + 7H20(1) 1.33Cl. (g) + 2e = 2C1 (ag)1.36MnO4 (ag) + 8H (aq) + 5e Mn (aq) + 4H2 O(1)2+1.49H2O2(aq) + 2H* (aq) + 2e 2H2 O(1)1.78S,03 (ag) + 2e = 2S0,2 (ag)2.01F2(g) + 2e 2F (ag)2.87Standard free-energy changekJ [ReferencCalculate the standard free-energy change at 25°C for the following reaction:4Cr(s) + 302 (g) + 12H*(ag) → 4Cr (ag) +6H,O(1)Use standard electrode potentials.Standard Electrode (Reduction) Potentials in Aqueous Solution at 25°CCathode (Reduction)StandardHalf-ReactionPotential, E (V)Lit (ag) +e=Li(s)Na* (aq) +e Na(s)-3.04-2.71Mg+ (ag) + 2e - Mg(s)-2.38Al+ (ag) + 3e - Al(s)-1,662H20(1) + 2e - H (g) + 20H (ag)-0.83Zn (ag) + 2e - Zn(s)-0.76Cr+ (ag) + 3e Cr(s)-0.74Fe?+ (aq) + 2e - Fe(s)-0.41Cd²+ (ag) + 2e - Cd(s)-0.40Ni?+ (ag) + 2e - Ni(s)-0.23Sn²+ (ag) + 2e Sn(s)-0.14Pb (ag) + 2e Pb(s)-0.13Fet (ag) +3e Fe(s)-0,042H (ag) + 2e H2 (g)0.00Sn (ag) +2e S (aq)2+0.15Cu²+ (aq) + e Cu* (aq)0.16Cu?+ (ag) + 2e - Cu(s)0.34IO (ag) + H2O(1) + 2e I(ag) + 20H (ag)0.49Cu* (ag) +e Cu(s)0.52L(s) + 2e 21 (ag)0.54A77Cengage Learning ( Cengage Technical Support

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[Referen Calculate the standard free-energy change at 25°C for the following reaction: 4Cr(s) + 302 (9) + 12H* (aq) + 4Cr** (aq) + 6H;O(1) Use standard electrode potentials. Standard Electrode (Reduction) Potentials in Aqueous Solution at 25C Standard Cathode (Reduction) Half-Reaction Potential, E (V) Lit (ag) +e Li(s) -3.04 Na* (ag) +e Na(8) Mg+ (aq) +2e Mg(s) 1, -2.71 -2.38 Al (aq) +3e Al(s) -1.66 2H20(1) + 2e H2 (g) + 20H (aq) Zn+ (ag) + 2e Zn(s) -0.83 -0.76 Crt (ag) +3e Cr(s) --0.74 Fe?+ (aq) + 2e Fe(s) -0.41 Cd²+ (ag) + 2e Cd(s) -0.40 Ni+ (ag) + 2e Ni(s) --0.23 Sn+ (ag) + 2e Sn(s) -0.14 Pb+ (ag) + 2e Pb(s) -0.13 Fet (aq)+3e Fe(s) -0.04 2H (ag) + 2e H2(9) 0.00 Sn (ag) + 2e Sn+ (aq) 0.15 Cu* (ag) +e Cu* (aq) 0.16 Cu+ (aq) + 2e Cu(s) 0.34 IO (aq) + H2O(1) + 2e I(aq) + 20H (aq) 0.49 Cu (aq) +e Cu(s) 0.52 L (s) +2e 21 (aq) 0.54 D.3+

[Referen Calculate the standard free-energy change at 25°C for the following reaction: 4Cr(s) + 302 (9) + 12H* (aq) + 4Cr** (aq) + 6H;O(1) Use standard electrode potentials. Standard Electrode (Reduction) Potentials in Aqueous Solution at 25C Standard Cathode (Reduction) Half-Reaction Potential, E (V) Lit (ag) +e Li(s) -3.04 Na* (ag) +e Na(8) Mg+ (aq) +2e Mg(s) 1, -2.71 -2.38 Al (aq) +3e Al(s) -1.66 2H20(1) + 2e H2 (g) + 20H (aq) Zn+ (ag) + 2e Zn(s) -0.83 -0.76 Crt (ag) +3e Cr(s) --0.74 Fe?+ (aq) + 2e Fe(s) -0.41 Cd²+ (ag) + 2e Cd(s) -0.40 Ni+ (ag) + 2e Ni(s) --0.23 Sn+ (ag) + 2e Sn(s) -0.14 Pb+ (ag) + 2e Pb(s) -0.13 Fet (aq)+3e Fe(s) -0.04 2H (ag) + 2e H2(9) 0.00 Sn (ag) + 2e Sn+ (aq) 0.15 Cu* (ag) +e Cu* (aq) 0.16 Cu+ (aq) + 2e Cu(s) 0.34 IO (aq) + H2O(1) + 2e I(aq) + 20H (aq) 0.49 Cu (aq) +e Cu(s) 0.52 L (s) +2e 21 (aq) 0.54 D.3+

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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