Heat Effects and Calorimetry 2. When 4.98 g of NaOH was dissolved in 49.72 g of water in a calorimeter at 23.7°C, the temperature of thesolution went up to 50.1°C.Is this dissolution reaction exothermic?a.Why?b. Calculate qH,O, using Equation 1.joulesс.Find AH for the reaction as it occurred in the calorimeter (Eq. 5).ΔΗ-joules d. Find AH for the dissolution of 1.00 g NaOH in water.AH =kJ/ge.Find AH for the dissolution of 1 mole NAOH in water.AH =kJ/molf.Given that NaOH exists as Na and OH¯ ions in solution, write the equation for the reaction thatoccurs when NaOH is dissolved in water.Given the following heats of formation, AH, in kJ per mole, as obtained from a table of AH, data,calculate AH for the reaction in Part (f). Compare your answer with the result you obtained in Part (e).NaOH(s), –425.6; Na*(aq), –240.1; OH (aq), –230.0g.ΔΗkJ/mol

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2. When 4.98 g of NaOH was dissolved in 49.72 g of water in a calorimeter at 23.7°C, the temperature of the solution went up to 50.1°C. Is this dissolution reaction exothermic? a. Why? b. Calculate 9H,0, using Equation 1. joules с. Find AH for the reaction as it occurred in the calorimeter (Eq. 5). ΔΗ- joules

2. When 4.98 g of NaOH was dissolved in 49.72 g of water in a calorimeter at 23.7°C, the temperature of the solution went up to 50.1°C. Is this dissolution reaction exothermic? a. Why? b. Calculate 9H,0, using Equation 1. joules с. Find AH for the reaction as it occurred in the calorimeter (Eq. 5). ΔΗ- joules

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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SUBJECT : GENERAL CHEMISTRY 2 TOPIC : HEAT AND CALORIMETRY
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