is number 9 correct? 8. If the accepted value for the heat of solution for NH,NO; is 25.69 kJ/mol, calculate the percent eryour answer – accepted answer% Error =x 100accepted answer一24.21×J/mol- 25-69k7lmel x/00% Error =25.69 KJ/mol% Error : 5. 80%This experiment does not consider that all of the conditions are standard state conditions; therefore, yare calculating AH501 not AH",sol•9. Calculate the final temperature of a solution prepared by dissolving 10.0g of NH,NO3 in 100.0water if the initial temperature of water is 25.0°C?Suppose AH = 25-69 KJ/molq= 10.0g xI baot25.69 kJ x 1000 J3D3209 J%D80.05gAT =3209 Ss=6.97 °c4.184 X/yC x I10y= T; * OT= 25.0 °C - 6.97°C18.0°C10 Would vou use ammonium nitrate to prepare a "cold pack" or a "hot pack"? Explain.

Molar enthalpy of solution is the amount of heat released or absorbed per mole of a substance. It is…

8. If the accepted value for the heat of solution for NH,NO, is 25.69 kJ/mol, calculate the percent er your answer- accepted answer x 100 % Error = accepted answer 124.2 KJ/mol 25.69 KT/mol x100 % Error = 35.69 KJ/mol % Error = 5. 80% This experiment does not consider that all of the conditions are standard state conditions; therefore, y are calculating AHgol not AH, sol· 9. Calculate the final temperature of a solution prepared by dissolving 10.0 g of NHẠNO; in 100.0 water if the initial temperature of water is 25.0°C? Suppose AH = 25-69 KJ/mol I DAot 80.05g 9= 10.0g x 25.64 KJ x. 1000J = 3209 J paot AT = 3209 = 6.9ラ °C 4. 184 XyC x I10y = Ti DT : 25.0 °C - 6.97 °C uld uou use ammonium nitrate to prepare a "cold pack" or a "hot pack"? Explain.

8. If the accepted value for the heat of solution for NH,NO, is 25.69 kJ/mol, calculate the percent er your answer- accepted answer x 100 % Error = accepted answer 124.2 KJ/mol 25.69 KT/mol x100 % Error = 35.69 KJ/mol % Error = 5. 80% This experiment does not consider that all of the conditions are standard state conditions; therefore, y are calculating AHgol not AH, sol· 9. Calculate the final temperature of a solution prepared by dissolving 10.0 g of NHẠNO; in 100.0 water if the initial temperature of water is 25.0°C? Suppose AH = 25-69 KJ/mol I DAot 80.05g 9= 10.0g x 25.64 KJ x. 1000J = 3209 J paot AT = 3209 = 6.9ラ °C 4. 184 XyC x I10y = Ti DT : 25.0 °C - 6.97 °C uld uou use ammonium nitrate to prepare a "cold pack" or a "hot pack"? Explain.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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