Consider the expression. 7.90 × 10–5 x(0.100 + x)? You can solve for x using a technique called successive approximations. Step 1: If you assume that x is very small compared to 0.100, such that 0.100 + x x 0.100, th (call it x1) can be calculated as 7.90 x 10-5 = x1 (0.100)² Calculate the first approximation of x. Express all answers to three or more significant figures. = Ix Step 2: Now, take your first approximation of x and plug it into the full equation. 7.90 × 10-5 = x2 (0.100 + x1)² Calculate the second approximation of x. X2 = Step 3: Each successive approximation uses the value from the previous approximation. 7.90 x 10-5 = x3(0.100 + x2)² Calculate the third approximation of x. X3 =
Consider the expression. 7.90 × 10–5 x(0.100 + x)? You can solve for x using a technique called successive approximations. Step 1: If you assume that x is very small compared to 0.100, such that 0.100 + x x 0.100, th (call it x1) can be calculated as 7.90 x 10-5 = x1 (0.100)² Calculate the first approximation of x. Express all answers to three or more significant figures. = Ix Step 2: Now, take your first approximation of x and plug it into the full equation. 7.90 × 10-5 = x2 (0.100 + x1)² Calculate the second approximation of x. X2 = Step 3: Each successive approximation uses the value from the previous approximation. 7.90 x 10-5 = x3(0.100 + x2)² Calculate the third approximation of x. X3 =
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Exergonic Reaction
The term exergonic is derived from the Greek word in which ‘ergon’ means work and exergonic means ‘work outside’. Exergonic reactions releases work energy. Exergonic reactions are different from exothermic reactions, the one that releases only heat energy during the course of the reaction. So, exothermic reaction is one type of exergonic reaction. Exergonic reaction releases work energy in different forms like heat, light or sound. For example, a glow stick releases light making that an exergonic reaction and not an exothermic reaction since no heat is released. Even endothermic reactions at very high temperature are exergonic.
Question
22.
Transcribed Image Text:Consider the expression.
7.90 x 10-5
3D х(0.100 + х)?
You can solve for x using a technique called successive approximations.
Step 1: If you assume that x is very small compared to 0.100, such that 0.100 + x z 0.100, then your first approximation of x
(call it x1) can be calculated as
7.90 x 10-5 = x1 (0.100)?
Calculate the first approximation of x. Express all answers to three or more significant figures.
X1 =
Step 2: Now, take your first approximation of x and plug it into the full equation.
7.90 x 10-5
%3D х2(0.100 + х,)?
Calculate the second approximation of x.
X2 =
Step 3: Each successive approximation uses the value from the previous approximation.
7.90 × 10-5 = x3(0.100 + x2)²
Calculate the third approximation of x.
X3 =
Transcribed Image Text:Step 4: Continue this process until two x values agree within the desired level of precision. Calculate the fourth and fifth
approximations of x.
X4 =
X5 =
Which values are the first to agree to two significant figures?
X3 and x4
X2 and x3
X4 and x5
O x1 and x2
Which values are the first to agree to three significant figures?
x3 and x4
X4 and x5
X1 and x2
X2 and x3
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