I Review I Constants I Periodic Table Sodium hydroxide reacts with carbon dioxide as follows: 2NAOH(s) + CO2 (g) → Na2 CO3 (s)+ H2O(1) Part A Which reagent is the limiting reactant when 2.30 mol NaOH and 1.20 mol CO, are allowed to react? O NAOH O CO2 Submit Request Answer

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Which reagent is the limiting reactant when 2.30 mol NaOH and 1.20 mol CO2 are allowed to react?

I Review I Constants I Periodic Table
Sodium hydroxide reacts with carbon dioxide as follows:
2NAOH(s) + CO2 (g) → Na2 CO3 (s) + H2O(1)
Part A
Which reagent is the limiting reactant when 2.30 mol NaOH and 1.20 mol CO2 are allowed to react?
NaOH
О СО2
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Transcribed Image Text:I Review I Constants I Periodic Table Sodium hydroxide reacts with carbon dioxide as follows: 2NAOH(s) + CO2 (g) → Na2 CO3 (s) + H2O(1) Part A Which reagent is the limiting reactant when 2.30 mol NaOH and 1.20 mol CO2 are allowed to react? NaOH О СО2 Submit Request Answer
Expert Solution
Analysis

Given : mole of NaOH = 2.30 mole 

             Mole of Carbon dioxide = 1.20 moles

To find: Limiting Reactant.

Concept : As we know that, in a chemical reaction the reactant that is present in less amount compared to other reactant is known as limiting reactant, while the reactant that is present in excess amount is known as excess reactant. 

Amout of reactants means mole of reactant. 

Mole of any compound is the ratio of mass of compound and molar mass of compound. 

Mole = mass / molar mass 

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