Consider an iron bar placed on a balance and the balance recording a weight of 75.0 g. As the iron bar begins to rust according to the reaction below, which of the following is true? Identify and briefly explain your answer. The reaction of the iron bar is as follows: 4 Fe (s) + 3 O2 (g) ⟶ 2 Fe2O3 (s) a) The weight of the iron bar will be less than 75.0 g.b) The weight of the iron bar will still be 75.0 g.c) The weight of the iron bar will be greater than 75.0 g.d) The weight of the iron bar will be greater than 75.0 g, but if the bar is removed and the rust is scraped off, the bar will again weight 75.0 g.

Iron reacts with oxygen to form iron(III) oxide. The equation for the balanced chemical reaction is as follows: 4 Fe (s) + 3 O2 (g) ⟶ 2 Fe2O3 (s) The stoichiometry of the balanced chemical reaction states that four moles of iron react with three moles of oxygen to form two moles of iron(III) oxide. We know that the molar mass of iron is = 55.845 g/mol Mass of four moles of iron = 4x55.845 = 223.38 Molar mass of iron(III) oxide is = 159.69 g/mol Mass of two moles of iron(III) oxide is = 159.69 x2 = 319.38 gHence we can say that 223.38 g of iron will form 319.38 g of iron(III) oxide.Final answer: The mass of iron is 75.0 g and the mass of rust, iron(III) oxide is 107.23 g. So the right option is: c) The weight of the iron bar will be greater than 75.0 g.

Answered: Consider an iron bar placed on a…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Consider an iron bar placed on a balance and the balance recording a weight of 75.0 g. As the iron bar begins to rust according to the reaction below, which of the following is true? Identify and briefly explain your answer.

The reaction of the iron bar is as follows: 4 Fe (s) + 3 O₂ (g) ⟶ 2 Fe₂O₃ (s)

a) The weight of the iron bar will be less than 75.0 g.

b) The weight of the iron bar will still be 75.0 g.

c) The weight of the iron bar will be greater than 75.0 g.

d) The weight of the iron bar will be greater than 75.0 g, but if the bar is removed and the rust is scraped off, the bar will again weight 75.0 g.

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