### Antacid Reaction Analysis#### Problem DescriptionAn old antacid commercial claimed that each tablet of their product could "neutralize 47 times its mass in stomach acid." The active ingredient in the antacid tablet, NaAl(OH)₂CO₃, reacts with HCl in stomach acid according to the following balanced chemical reaction:\[ \text{NaAl(OH)}_2\text{CO}_3 + 4 \text{HCl} \rightarrow \text{NaCl} + \text{AlCl}_3 + 3 \text{H}_2\text{O} + \text{CO}_2 \]**Question 1:** How many moles of HCl can a 1.03 g antacid tablet neutralize if the tablet contains 0.246 g of the active ingredient?#### Additional QuestionIf stomach acid has a concentration of 0.14 M HCl, assuming the density of stomach acid to be similar to that of water (1.00 g/mL), what is the mass of stomach acid that the 1.03 g of antacid tablet can neutralize? Does this number support the claim in the commercial?#### AnalysisTo solve these questions, you'll need to:1. Calculate the moles of NaAl(OH)₂CO₃ in the tablet.2. Use stoichiometry to find the moles of HCl that can be neutralized.3. Calculate the equivalent mass of stomach acid based on its concentration.4. Compare this mass to the mass of the antacid to verify the commercial's claim. Use these calculations as an educational exercise in stoichiometry and chemical reaction analysis.

0.0068 moles of HCl is required to neutralize the antacid tablet. The equation of the reaction…

4. An old antacid commercial claimed that each tablet of their product could "neutralize 47 times its mass in stomach acid". The active ingredient in the antiacid tablet, NaAl(OH)₂CO3, reacts with HCl in stomach acid according to this balanced reaction: NaAl(OH)₂CO3 + 4 HCl →→ NaCl + AlCl3 + 3H₂O + CO₂ How many moles of HCl can a 1.03 g of antiacid tablet neutralize if the tablet contains 0.246 g of the active ingredient?

4. An old antacid commercial claimed that each tablet of their product could "neutralize 47 times its mass in stomach acid". The active ingredient in the antiacid tablet, NaAl(OH)₂CO3, reacts with HCl in stomach acid according to this balanced reaction: NaAl(OH)₂CO3 + 4 HCl →→ NaCl + AlCl3 + 3H₂O + CO₂ How many moles of HCl can a 1.03 g of antiacid tablet neutralize if the tablet contains 0.246 g of the active ingredient?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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