I need some code redone, I have a basic setup of the code but I would like to make a few minor changes to it, basically, in c prgramming, in the graph shown below, if a user were to input the value of .8907, the z value returned from the code would be .03 + 1.2 = 1.23. I would like to understand the new coded you provide so if you could use comments as well that would be awesome! ### C Program to Read and Process Data from a FileBelow is a C program that reads data from a file named "Distribution.txt" and processes it to find the closest z-value. The program ensures the input falls within a specified range and performs calculations to find the nearest z-value from the data read.```c#include int main(){ double z_array [40][10]; double z; FILE *f = fopen ("Distribution.txt", "r"); for (int i = 0; i < 40; i++) { fscanf (f, "%lf", &z); for (int j = 0; j < 10; j++) fscanf (f, "%lf", &z_array [i][j]); } fclose (f); while (1) { printf ("Values greater than one and less than .5 will not be accepted: "); scanf ("%lf", &z); if ((z < 0.5) || (z > 1)){ break; } } int i, j; double prev; for (i = 0; i < 40; i++) { for (j = 0; j < 10; j++) { if (z_array [i][j] > z) break; else prev = z_array [i][j]; } if (z_array [i][j] > z) break; } if ((z - prev) < (z_array [i][j] - z)) { // previous item is nearest if (j > 0) j--; else { i--; j = 9; } } double zval = i * 0.1 + j * 0.01; printf ("%0.4lf's z-value is %0.2lf\n", z, zval);}```### Explanation**1. Including the Header File:**```c#include ```This includes the standard input-output library used for file manipulation and console I/O.**2. Defining the Main Function:**```cint main() {```This defines the main function which serves as the entry point of the program.**3. Declaring Variables:**```cdouble z_array[40][10]; ### z-Score TableThe table provided is a portion of the standard normal distribution table, commonly used in statistics to find the probability that a statistic is observed below, above, or between certain values. This is also known as a z-table.#### Understanding the TableEach cell in the table represents the cumulative probability from the mean to a specific z-score. The cumulative probability is a way of representing the area under the curve for the standard normal distribution.- **First Column (z):** This column represents the z-score ranging from 0.0 to 1.2 in increments of 0.1.- **Top Row (Decimal part):** This row represents the second decimal place of the z-score, ranging from 0.00 to 0.09.#### Example ExplanationTo find the cumulative probability for a z-score of 1.23:1. Locate the value in the first column ("1.2").2. Locate the value in the top row ("0.03").3. The intersection of the row and column gives the cumulative probability.In this case, if you look at the row for 1.2 and the column for 0.03, the intersecting value is **0.8907**. This means that approximately 89.07% of the distribution is below a z-score of 1.23.#### Highlighted Example- The row with z = **1.2** is highlighted.- The column corresponding to the decimal part **0.03** is highlighted.- The intersecting value (highlighted) for a z-score of **1.23** is **0.8907**.This representation is crucial for many statistical methods including hypothesis testing, confidence intervals, and more, providing a standardized method for comparing different datasets and observations.

Note: I have used a few records in the file for printing the output. You can add all the rows and…

Answered: I need some code redone, I have a basic…

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

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I need some code redone, I have a basic setup of the code but I would like to make a few minor changes to it, basically, in c prgramming, in the graph shown below, if a user were to input the value of .8907, the z value returned from the code would be .03 + 1.2 = 1.23.

I would like to understand the new coded you provide so if you could use comments as well that would be awesome!