A Web site validates a 16-digit ID number based on the following rules - 1. Starting with the leftmost digit, double it and then double every other digit after it. However, if any of the doubled digits is a two-digit number, subtract 9 from it. Then sum these new digits. For instance, if the ID card number is 5866793610024475, then the digits considered are 5, 6, 7, 3, 1, 0, 4, 7, their new replacements are 1, 3, 5, 6, 2, 0, 8, 5 and the sum of the replacement is 30. 1 3 4 5 7 9. 10 11 12 13 14 15 5 8 6 6. 7 9 3 6. 1 4 4 7 5 5 6 7 1 4 7 5*2-9 6*2-9 7*2-9 3*2 1*2 0*2 4*2 7*2-9 =1 =3 =5 =6 =2 =0 =8 =5 2. Sum together the remaining sever digits from the ID card number. That is, the digits in the odd-numbered positions. With the ID card number above, we obtain 8+6+9+6+0+2+4+5 =40. 3. Add together the two sums. If the result is a multiple of 10, then accept the ID card number. Otherwise, reject it. We accept the ID card number since 30+40=70, a multiple of 10. Write a program that perform data validation on an ID card number. See Output Examples below: Output Examples Enter ID card number: 5866793610024475 The number, 5866793610024475, is valid. Enter ID card number: 5686793610024475 The number, 5686793610024475, is not valid. Enter ID card number: 8566793610024457 The number, 8566793610024457, is not valid. Enter ID card number: 586679361024475 Must enter 16-digit ID numbers. The number, 586679361024475, is not valid. Enter ID card number: abc Must enter 16-digit ID numbers. The number, abc, is not valid. Enter ID card number: Must enter 16-digit ID numbers. The number, , is not valid.

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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NEED HELP WITH PYTHON CODE. ALSO, PLEASE PROVIDE DETAILS SEPARATELY ON HOW AND WHAT DID U USE TO GET UR CODE DONE. 

# ID Number Validation Process

This educational content outlines the process for validating a 16-digit ID number. The validation follows a structured algorithm, including calculations and checks, as detailed below.

### Validation Steps:

1. **Initial Calculations:**
   - Begin with the leftmost digit, double it, and continue doubling every other digit following it.
   - If doubling results in a two-digit number, subtract 9 from it.
   - Sum these adjusted digits.

   **Example:**
   - ID number: 5866793610024475
   - Digits: 5, 6, 7, 3, 1, 0, 4, 7
   - Replacements and their sums are:
     - Step 1 replacements: 5, 6, 7, 3, 1, 0, 4, 7 → produces 1, 3, 5, 6, 2, 0, 8, 5
     - Total replacement sum: 30

   **Detailed Table:**

   | Original Digit | Replaced with | Calculation        |
   |----------------|---------------|--------------------|
   | 5              | 1             | 5×2−9 = 1          |
   | 6              | 3             | 6×2−9 = 3          |
   | 7              | 5             | 7×2−9 = 5          |
   | 3              | 6             | 3×2 = 6            |
   | 1              | 2             | 1×2 = 2            |
   | 0              | 0             | 0×2 = 0            |
   | 4              | 8             | 4×2 = 8            |
   | 7              | 5             | 7×2−9 = 5          |

2. **Sum Remaining Digits:**
   - Add the remaining unadjusted digits (in the odd-numbered positions).
   - Example Result: 8+6+9+6+0+2+4+4+5 = 40

3. **Final Sum Check:**
   - Combine the sum from adjustments (30) and the sum of odd-position digits (40).
   - Result: 30 + 40 = 70
   - Check if
Transcribed Image Text:# ID Number Validation Process This educational content outlines the process for validating a 16-digit ID number. The validation follows a structured algorithm, including calculations and checks, as detailed below. ### Validation Steps: 1. **Initial Calculations:** - Begin with the leftmost digit, double it, and continue doubling every other digit following it. - If doubling results in a two-digit number, subtract 9 from it. - Sum these adjusted digits. **Example:** - ID number: 5866793610024475 - Digits: 5, 6, 7, 3, 1, 0, 4, 7 - Replacements and their sums are: - Step 1 replacements: 5, 6, 7, 3, 1, 0, 4, 7 → produces 1, 3, 5, 6, 2, 0, 8, 5 - Total replacement sum: 30 **Detailed Table:** | Original Digit | Replaced with | Calculation | |----------------|---------------|--------------------| | 5 | 1 | 5×2−9 = 1 | | 6 | 3 | 6×2−9 = 3 | | 7 | 5 | 7×2−9 = 5 | | 3 | 6 | 3×2 = 6 | | 1 | 2 | 1×2 = 2 | | 0 | 0 | 0×2 = 0 | | 4 | 8 | 4×2 = 8 | | 7 | 5 | 7×2−9 = 5 | 2. **Sum Remaining Digits:** - Add the remaining unadjusted digits (in the odd-numbered positions). - Example Result: 8+6+9+6+0+2+4+4+5 = 40 3. **Final Sum Check:** - Combine the sum from adjustments (30) and the sum of odd-position digits (40). - Result: 30 + 40 = 70 - Check if
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