I have a question this solution that I looked up. My question is where the bold italicized numbers came from. 1) For this part n=30 So for this the standard deviation is= 10030√10030 So the required probability is: P(||X⎯⎯⎯−273||≤16)=P(−16≤X⎯⎯⎯−273≤16) =P(−1610030√≤X⎯⎯⎯−27310030√≤1610030√) =P(−0.876356≤Z≤0.876356) =P(Z≤0.876356)−P(Z<−0.876356) =0.8096−0.1904=0.6192
I have a question this solution that I looked up. My question is where the bold italicized numbers came from. 1) For this part n=30 So for this the standard deviation is= 10030√10030 So the required probability is: P(||X⎯⎯⎯−273||≤16)=P(−16≤X⎯⎯⎯−273≤16) =P(−1610030√≤X⎯⎯⎯−27310030√≤1610030√) =P(−0.876356≤Z≤0.876356) =P(Z≤0.876356)−P(Z<−0.876356) =0.8096−0.1904=0.6192
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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I have a question this solution that I looked up. My question is where the bold italicized numbers came from.
1) For this part n=30
So for this the standard deviation is= 10030√10030
So the required
P(||X⎯⎯⎯−273||≤16)=P(−16≤X⎯⎯⎯−273≤16)
=P(−1610030√≤X⎯⎯⎯−27310030√≤1610030√)
=P(−0.876356≤Z≤0.876356)
=P(Z≤0.876356)−P(Z<−0.876356)
=0.8096−0.1904=0.6192
Answer(1): 0.6192
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