2 The time to complete the eight-mile run around Mackinaw Island has a normal distribution The mean time for a population of runners to complete the run is 56 minutes, and standard deviation is a 5 Determine the probability that the time to complete the run of a randomly selected runner is at least 48 minutes, but less than 50 minutes Definition of X X is the time to complete the run of a randomly selected runner Probability statement in ter of X Note: Show me how you determine the values for Z Probability statement in terms of Z Prob

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A: Mean=211 Standard deviations=18

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A: According to the given information, we haveThe mean of the distribution is 29 minutes.The standard…

Q: Assume that adults have IQ scores that are normally distributed with a mean of u = 105 and a…

A: mean(μ)=105standard deviation(σ)=20

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A:

Q: Assume that adults have IQ scores that are normally distributed with a mean of μ=105 and a standard…

A: Let denote the adults have IQ scores that are normally distributed.Given that,The mean:…

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A: Given data,μ=100σ=10

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A: Given : Mean = x = 226.8 Standard deviation = s = 1.9 sample size = n = 27

Q: d. What is the probability that the sample mean will be between 250 pounds and 257 pounds? P (250…

A: Given that μ=247.2,σ=35,n=34

Q: IQ is normally distributed with a mean of 100 and a standard deviation of 15. Suppose one individual…

A: let X: IQ X~N(μ,σ)where, mean(μ)=100    and standard deviation(σ)=15

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A: Given Information:  Mean (u) = 76 mph  Standard deviation (s) = 6 mph

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A: Population mean μ =2.5 Population standard deviation =0.25 Sample size n =60 Standard error=S.D/√n…

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A:

Q: Assume that adults have IQ scores that are normally distributed with a mean of μ=105 and a standard…

A: given datanormal distributionμ= 105σ = 15P(x<120) = ?

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A: We will solve the following

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A: Given : Population Mean,μ = 18.0 Population Standard Deviation,σ = 6.0

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A: List of formulae :  Mean :  μ= ∑xP(x) Standard deviation :  σ = ∑(x-μ)2P(x)

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Q: Assume that adults have IQ scores that are normally distributed with a mean of μ = 105 and a…

A: normal distributionμ = 105σ = 15P(86<x<124) = ?

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A: Given that  H0:μ=80Ha:μ≠80 Given that μ=80σ=16n=8x¯=74 Test statistic: z=x¯-μσn =74-80168 =-1.0607

Q: How do I do this problem?

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Q: 1. The weights of fish in a certain lake are normally distributed with a mean of 12 pounds and a…

A: