I am only interested in part 6-27(a). I see that Bartleby has answered this question before but I have a question regarding the yielding factor of safety. Why is the yielding factor of safety calculated as ( n=Sy/sigma_max), but not as ( n=Sy/Kt*sigma_max )? Since there is a stress concentration factor and the sigma_max is technically considered the nominal stress. (6-27 Using the Goodman criterion for infinite life, repeat Problem 6-25 for each of thefollowing loading conditions:(a) 0 kN to 28 kN(b) 12 kN to 28 kN(c) 28 kN to 12 kN6-25 The cold-drawn AISI 1040 steel bar shown in the figure is subjected to a completelyreversed axial load fluctuating between 28 kN in compression to 28 kN in tension.Estimate the fatigue factor of safety based on achieving infinite life and the yielding.factor of safety. If infinite life is not predicted, estimate the number of cycles to failure.em 6-2525 mm10 mm6-mm D.

The material is 1040 steel bar,

I am only interested in part 6-27(a). I see that Bartleby has answered this question before but I have a question regarding the yielding factor of safety. Why is the yielding factor of safety calculated as ( n=Sy/sigma_max), but not as ( n=Sy/Kt*sigma_max )? Since there is a stress concentration factor and the sigma_max is technically considered the nominal stress.

I am only interested in part 6-27(a). I see that Bartleby has answered this question before but I have a question regarding the yielding factor of safety. Why is the yielding factor of safety calculated as ( n=Sy/sigma_max), but not as ( n=Sy/Kt*sigma_max )? Since there is a stress concentration factor and the sigma_max is technically considered the nominal stress.

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter8: Applications Of Plane Stress (pressure Vessels, Beams, And Combined Loadings)

Section: Chapter Questions

Problem 8.5.32P

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