HW3: Graphing trip functions (4.5, 4.8) Question 12 of 17 (1 point) I Question Attempt: 1 of 3 Which one of the following choices could be the average rate of change of f(x) = cos x from 6 to 0? 00.13 00 00.31 -0.03 (d) Fill in the blank in the statement below. For an x-value that is greater than 0 but less than (Choose one) , the average rate of change of the function f from 0 to x is Save For

HW3: Graphing trip functions (4.5, 4.8) Question 12 of 17 (1 point) I Question Attempt: 1 of 3 Which one of the following choices could be the average rate of change of f(x) = cos x from 6 to 0? 00.13 00 00.31 -0.03 (d) Fill in the blank in the statement below. For an x-value that is greater than 0 but less than (Choose one) , the average rate of change of the function f from 0 to x is Save For

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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▼ Part A Find AHn for the following reaction: Use the following reactions with known AH values: Express the energy to one decimal place and include the appropriate units. AHrx = Submit μA - 1970.8 S X Incorrect; Try Again kJ Previous Answers Request Answer 2H₂S(g) + O2(g) →2S(s, rhombic) + 2H₂O(g) S(s, rhombic) + O2(g) →→SO₂(g) PbO(s) + H₂S(g) → PbS(s) 2PbS(s) +302(g) → 2PbO(s) +2SO2(g) ? keyboard shortcuts + H₂O(g) AH-442.4 kJ AH-296.8 kJ ΔΗ AH-104.3 kJ
Volume of liom NaoH (mk) = 26.21 26.1 Mass of 1om Hcl(@) = %3D initial temperature (c) Final Madimum temporatule c) = 23.1 AT(OC)= 4 : 19.1 Moles of H = ? %3D Moles of OH (mo) =? Moles of H20 formed Conarl)=? Heat envolued e9raickon) (5)= ? Hot Gpacits of Colomoter (ecal in I/ocs = ? Average heut Capacits of Colorimder lG/9c) =
Solve the following expression for x. What is (are) the value(s) of the positive root(s)? (x - 0.400)² 2.0 + X un for additional resources = 1.59 A) 0.400 B) 2.86 C) 1.39 D) 3.30 Submit
Which of the following must be true if the steady state assumption is to be used? Ok₁[E][S] = k₂[ES] d[ES]/dt = 0 O[E]T=[ES] k₁[E][S]=k₂[ES] -k.₁[ES] (k₂-k.1)/k₁ = 1
1. HBr +O2 →HOOBF 2(g) (slow) 2. НООBr + HBr, (8) 2HOB" 2g) (fast) 3. 2{НОBr + HBr, T →H,O« +Br} (fast) (8) (g) 2(g) 4HB +0,→2H,O, +2Br%e - (3) Consider the above reaction mechanism. The rate-law equation from this reaction would be - K[HOB1]*[HBr] K[HBr]*[O,] = k[HOB1]² r = k[HBr]'[O,]' а. r = d. = b. e. impossible to tell from this information r = с.
Predicting relative forward and reverse rates of reaction in a... Acetic acid and ethanol react to form ethyl acetate and water, like this: HCH,CO,(aq)+c,H,OH(aq) → C,H,CO,CH;(aq)+H,0(1) Imagine 137. mmol of c,H,CO,CH, are removed from a flask containing a mixture of HCH3CO,, C2H¿OH, C,H,CO,CH; and H,0 at equilibrium, and then answer the following questions. O Zero. What is the rate of the reverse reaction before any C2H5CO2CH3 has been removed from the flask? O Greater than zero, but less than the rate of the forward reaction. Greater than zero, and equal to the rate of the forward reaction. Greater than zero, and greater than the rate of the forward reaction. O Zero. What is the rate of the reverse Greater than zero, but less than the rate of the forward reaction. reaction just after the C2H5CO2CH3 has been removed from the flask? Greater than zero, and equal to the rate of the forward reaction. Greater than zero, and greater than the rate of the forward reaction. Zero. What is the…
3. The reaction H₂SO3(aq) + 6(aq) + Haq) → Se(s) +213(aq) + 3H₂0 (1) was studied at 0°C. The following data were obtained: Experiment # 1 2 3 4 5 6 7 [H₂SO3(aq)lo (mol/L) constant? 1.0 x 104 2.0 x 10-4 3.0 x 104 1.0 x 10-4 1.0 x 10-4 1.0 x 104 1.0 x 104 [¹] (mol/L) 2.0 x 10² 2.0 x 10-² 2.0 x 10-² 4.0 x 10-² 1.0 x 10-² 2.0 x 10-² 1.0 x 10-² Find the order of the reaction with respect to [H₂SO3]. respect to [I-¹]. reaction with respect to [H+¹]. is the overall order of the reaction? Find the value of the rate constant (k). Only write the number. [H¹+] (mol/L) 2.0 x 10-² 2.0 x 10-² 2.0 x 10-² 2.0 x 10-² 2.0 x 10-² 4.0 x 10-² 4.0 x 10-² Rate (mol/L.s) Find the order of the reaction with Find the order of the What What are the units of the rate 1.66 x 10-7 3.33 x 10-7 4.99 x 10¹7 6.66 x 10-7 0.42 x 10-7 13.2 x 10-7 3.36 x 10-7
Calculate AH for the reaction below
Next, the following equation describes the polynomial curve to the [SO₂Cl₂] versus time data was received: [SO₂Cl₂] = 4.93 × 10-8 t² - 1.16 × 10-4 t +9.90 × 10-² Which of the following equation describes best the first derivative of the best fit curve: d [SO₂Cl₂] dt d [SO₂Cl₂] dt d [SO₂Cl₂] dt Od [SO₂Cl2] dt (a) at 200 min: i (4.93 × 10-8)t - 1.16 × 10−4 = 2(4.93 × 10−8)t – 1.16 × 10−4 + 9.90 × 10-² 2(4.93 × 10-8)t – 1.16 × 10-4 = : (4.93 × 10−8)t – 2(1.16 × 10−4) Calculate slope of the tangent of the first derivative. Use scientific notation, e.g. enter 2E3 for 2000. Enter your answer with one significant figure. (b) at 600 min i = M min-¹ M min -1 Finally, compare the graphically determined instantaneous rate of decomposition at 200 min (A) and at 600 min (B) to the slope of the tangent of the first derivative at 200 min (a) and at 600 min (b): The positive of the values of the slope of the tangent of the first derivative are far close identical to the graphically determined rates.
8:53 Question 28 of 40 2 5 8 One of the fastest pitches ever thrown in Major League Baseball was by Aroldis Chapman and had a velocity of 105.1 miles/hour. How many seconds did it take this pitch to travel the 60 feet and 6 inches from the pitcher's mound to home plate? (1 mile = 5280 feet) 1 4 7 +/- Tap here or pull up for additional resources S 3 6 9 O ..lLTE Submit XU x 100
P5.1. Calculate ArxnSoof the reaction: + ½ Ozle) H,Oe) a. at 25 °C b. at 1000 °C Given: 5° /R at 25 °C: H2ie): 15.7041 O2le): 24.6604 H,0R: 22.6984 Cp /R at the temperature range: H2le): 3.4958 - 0.1006 x 103 T/(K) + 2.419 x 107 T²/(K²) Ozleg: 3.0673 + 1.6371 x 103 T/(K) + 5.118 x 107 T/(K?) H,0je: 3.6330 + 1.1950 x 10-3 T/(K) + 1.340 x 10-7 T2/(K2)