Next, the following equation describes the polynomial curve to the [SO₂Cl₂] versus time data was received: [SO₂Cl₂] = 4.93 × 10-8 t² - 1.16 × 10-4 t +9.90 × 10-² Which of the following equation describes best the first derivative of the best fit curve: Od [SO₂Cl₂] = dt Od [SO₂Cl₂] = dt Od [SO₂Cl₂] dt Od [SO₂Cl₂] dt (a) at 200 min: i (b) at 600 min i (4.93 x 10-8)t - 1.16 × 10-4 2(4.93 × 10-8)t - 1.16 × 10-4 +9.90 × 10-² = 2(4.93 × 10-8)t - 1.16 × 10-4 (4.93 × 10-8)t - 2(1.16 × 10-4) = Calculate slope of the tangent of the first derivative. Use scientific notation, e.g. enter 2E3 for 2000. Enter your a significant figure. M min-1 M min-1
Next, the following equation describes the polynomial curve to the [SO₂Cl₂] versus time data was received: [SO₂Cl₂] = 4.93 × 10-8 t² - 1.16 × 10-4 t +9.90 × 10-² Which of the following equation describes best the first derivative of the best fit curve: Od [SO₂Cl₂] = dt Od [SO₂Cl₂] = dt Od [SO₂Cl₂] dt Od [SO₂Cl₂] dt (a) at 200 min: i (b) at 600 min i (4.93 x 10-8)t - 1.16 × 10-4 2(4.93 × 10-8)t - 1.16 × 10-4 +9.90 × 10-² = 2(4.93 × 10-8)t - 1.16 × 10-4 (4.93 × 10-8)t - 2(1.16 × 10-4) = Calculate slope of the tangent of the first derivative. Use scientific notation, e.g. enter 2E3 for 2000. Enter your a significant figure. M min-1 M min-1
Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter5: Principles Of Chemical Reactivity: Energy And Chemical Reactions
Section5.8: Product- Or Reactant-favored Reactions And Thermodynamics
Problem 2.1ACP
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![Next, the following equation describes the polynomial curve to the [SO₂Cl₂] versus time data was received:
[SO₂Cl₂] = 4.93 × 10-8 t² - 1.16 × 10-4 t +9.90 × 10-²
Which of the following equation describes best the first derivative of the best fit curve:
d [SO₂Cl₂]
dt
d [SO₂Cl₂]
dt
d [SO₂Cl₂]
dt
Od [SO₂Cl2]
dt
(a) at 200 min: i
(4.93 × 10-8)t - 1.16 × 10−4
= 2(4.93 × 10−8)t – 1.16 × 10−4 + 9.90 × 10-²
2(4.93 × 10-8)t – 1.16 × 10-4
=
: (4.93 × 10−8)t – 2(1.16 × 10−4)
Calculate slope of the tangent of the first derivative. Use scientific notation, e.g. enter 2E3 for 2000. Enter your answer with one
significant figure.
(b) at 600 min i
=
M min-¹
M min -1
Finally, compare the graphically determined instantaneous rate of decomposition at 200 min (A) and at 600 min (B) to the slope of
the tangent of the first derivative at 200 min (a) and at 600 min (b):
The positive of the values of the slope of the tangent of the first derivative are
far
close
identical
to the graphically determined rates.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F470b6100-4106-4b23-8cac-2365db91c4dd%2Fab04b26f-9aec-43c5-aeb9-a0d84e828cda%2Fin5po6i_processed.png&w=3840&q=75)
Transcribed Image Text:Next, the following equation describes the polynomial curve to the [SO₂Cl₂] versus time data was received:
[SO₂Cl₂] = 4.93 × 10-8 t² - 1.16 × 10-4 t +9.90 × 10-²
Which of the following equation describes best the first derivative of the best fit curve:
d [SO₂Cl₂]
dt
d [SO₂Cl₂]
dt
d [SO₂Cl₂]
dt
Od [SO₂Cl2]
dt
(a) at 200 min: i
(4.93 × 10-8)t - 1.16 × 10−4
= 2(4.93 × 10−8)t – 1.16 × 10−4 + 9.90 × 10-²
2(4.93 × 10-8)t – 1.16 × 10-4
=
: (4.93 × 10−8)t – 2(1.16 × 10−4)
Calculate slope of the tangent of the first derivative. Use scientific notation, e.g. enter 2E3 for 2000. Enter your answer with one
significant figure.
(b) at 600 min i
=
M min-¹
M min -1
Finally, compare the graphically determined instantaneous rate of decomposition at 200 min (A) and at 600 min (B) to the slope of
the tangent of the first derivative at 200 min (a) and at 600 min (b):
The positive of the values of the slope of the tangent of the first derivative are
far
close
identical
to the graphically determined rates.
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