I got 2.71 and it says its wrong can someone explain please **Lab Skills: Using Volumetric Glassware for Dilutions****Laboratory Simulation****Question 1:**How many grams of copper(II) sulfate pentahydrate $(\text{CuSO}_4 \cdot 5 \text{H}_2\text{O})$ are needed to prepare 100.00 milliliters of a 0.17 M copper(II) sulfate solution?Answer in grams: [________] g---**Instructional Elements:**- **Phase 1:** Mass of solute needed to prepare stock solution - Complete the following step: 1. Answer question 1 **Additional Resources:**- **Methods**- **Reset**- **My Notes**- **Lab Data** There is a navigation panel with the label "PHASES" currently highlighting Phase 1 and an option to proceed to Phase 2.Make use of the "How to Calculate Mass of Solute Needed to Prepare Solution" guide for assistive calculations.

The amount of solute present in a solution is expressed in terms of concentration. It is expressed…

How to Calculate Mass of Solute Needed to Prepare Solution 1) How many grams of copper(II) sulfate pentahydrate (CuSO4 - 5 H₂O) are needed to prepare 100.00 milliliters of a 0.17 M copper(II) sulfate solution? 9

How to Calculate Mass of Solute Needed to Prepare Solution 1) How many grams of copper(II) sulfate pentahydrate (CuSO4 - 5 H₂O) are needed to prepare 100.00 milliliters of a 0.17 M copper(II) sulfate solution? 9

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Hi! Is this correct? Kc = [N2O] [NO2] / [NO]^3
View History Bookmarks Develop Window Help A east.cengagenow.com [References) 1 pt EXERCISE Unit Conversion 1 pt Drag conversion units onto the boxes in the equation to make conversions. Some boxes can be left empty. Click on a unit to remove it from its position. 1 pt 1 cm³ Cu 9 g Cu 9.5 x 1021 atoms Cu 1 g Cu 1 pt 1 kg 1000 g 1 cm = 1 mL 1 pt 1 L 1000 cm3 1 pt 1 pt 520 L x 1 pt 1 pt 1 pt A piece of copper has a volume 520 L. What is the mass of the sample, in units of grams? In the boxes above, enter the correct setup that would be used to solve this problem. 1 pt 1 pt Check Next (2 of 3) 1 pt 1 pt Submit Answer Try Another Version 2 item attempts remaining 1 pt
18E(S) + SHOCAL) → 2 EeU₂(3) + 3H₂(g) FeU2(s) ○ 4.525€ > 0 0 4,5%, 0120 O A, S., 0 40 Q Search ******* ******* D ******* ****** ****** 24 $1
Find the missing values represented by shapes.
1211 120 110- 100- 9어 1986,46cm-1, 92.30%T 1888.12cm-1, 86.12%T 523.69çof-1. 89.49%T 2115.07cm-1, 87,12%T 80- 2868.59cm-1, 81.50%T 2324.95cm-1, 80.38%T 3056.42cm-1, 78.57%T 550.70cm-1. 78.65%T 1702.35cm-1, 76.07%f 1927.16cm-1. 77.87%T 70- 564.67m-1, 79.00%T 1075 B3cm-1, 73.25%T 1998.63cm-1, 70.10%T 615,31cm-1. 70.28%T 596.43cm-1, 73.02%T 1175.49bm-1 68.00%T 1220.95cm-1, 70.17%T 1321.38cm-1, 65.41% 813.05cm-1 67.15%T 864.57cm-1, 70 74%T 1150.80cm-1, 71.53%T 764.65cm-1, 61.64%T 944.04cm-1|60.89%f 935.39cm-1, 61.19%T 918.05cm-1, 57.40%T 1160.53cm-1, 71.59%T 785.46cm-1, 79.57% 60- 1575.58cm-1, 58.026T 1447.52cm-1, 57.15%T 504.91cm-1, 67.34%T 1593.50cm-1, 54.46%T spom-1. 50- 702.64cm-1. 50d.16%T 692.96cm-1, 4.59%T 1650.46cm-1, 50.27%T 1274.05cm-1, 46.51%T 40- 636.49cm-1, 49.33%T 30- 20- 508.62cm1, 24.70%T 514.69cm-1. 26.58%T 10 94 4000 3500 3000 2500 2000 1500 1000 500 cm-1 Name Description Sample 2a 1 067 By Analyst Date Tuesday, July 07 2020 for
Rearrange this equation to isolate c. a = b ( ²/² - 1/2 ) C C = 2 Please leave no spaces, use only parenthesis, not brackets, and use "/" for division. a=((fc/(d-e))-b)/c
Also we have a mixture for gas is hydrogen helium neon and nitrogen sealed in a container of -50 Celsius degree so imaginary pick one molecule and follow it around for some time and record speed we determine that on average a small chill travels with speed of approximately 1.9x10^3 km/h . Which molecule or atom did we pick up MM,g/mol Hydrogen 2.02 Helium 4.00 Neon 20.18 Nitrogen 28.01
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Mail - Mary X D21 Grades - Sp X G when does X Submit Answer AT HOMEWOR 735112480241329813180832311&elSBN=9781305862883&id=1707785907&snapshot!.... References A X Sample A is found to contain 34.9 g of nitrogen and 39.9 g of oxygen. Sample B is found to contain 87.9 g of nitrogen and 201 g of oxygen. Och.1 classif x of Definite and Multiple Proportions: This is group attempt 1 of 10 Use the References to access important values if needed for this question. Two samples that are known to come from binary compounds of nitrogen (N) and oxygen (0) are analyzed. Autosaved at 10:33 PM G Do samples A and B obey the law of definite proportions, the law of multiple proportions, both laws, or neither law? Could A and B be samples of the same compound or are they different compounds? MindTap - ( X Q Search this ☐ Regenerate G
SC Score: 0 of 1 point Incorrect Your answer is wrong. In addition to checking your math, check that you used the right data and DID NOT round any intermediate calculations. Steam reforming of methane (CH4) produces "synthesis gas," a mixture of carbon monoxide gas and hydrogen gas, which is the starting point for many important industrial chemical syntheses. An industrial chemist studying this reaction fills a 75.0 L tank with 14. mol of methane gas and 5.8 mol of water vapor, and when the mixture has come to equilibrium measures the amount of carbon monoxide gas to be 2.3 mol. Calculate the concentration equilibrium constant for the steam reforming of methane at the final temperature of the mixture. Round your answer to 2 significant digits. Answer Submitted: A K = 18 Submitted: Mar 2 10:23 PM Correct Answer: 0.0033 Assignments List ! F @ Review Assignment Time Spent: 39m 5s # с $ MacBook Pro G Search or type URL % & + © 2023 McGraw Hill LLC. All Rights Reserved. Terms of Use |…
Make a dilution series to get to 1:100. Start with making 1:10 dilution by adding 1mL of sample and 9mL of diluent, now continue the series to get to 1:100. The formula you may use is V1D1=V2D2
H. NH₂ H NaBH3CN (C8H15N)