A particular beer is 6.50% ethanol by volume (C₂H₂O). If a single bottle of beer contains 750.0 mL of beer, what mass, in g of ethanol (C₂H₂O), is present in the bottle? The density of ethanol is 0.789 g ethanol/mL ethanol

Chemistry: Matter and Change
1st Edition
ISBN:9780078746376
Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Chapter3: Matter-properties And Changes
Section3.4: Elements And Compounds
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Please set up the answer the correct way. I am having a hard time with putting the units in the correct spots. 

### Problem Statement
A particular beer is **6.50 % ethanol by volume (C₂H₆O)**. If a single bottle of beer contains **750.0 mL of beer**, what mass, in **g of ethanol (C₂H₆O)**, is present in the bottle? The density of ethanol is **0.789 g ethanol/mL ethanol**.

### Diagram Explanation

#### Equation Setup:
The diagram helps set up the calculation as follows:

**Starting Amount:**
- Initial volume of beer available, given as 750.0 mL.

**Calculation Formula:**
The diagram provides a structure to solve the problem step-by-step visually, using multiplication and unit conversions.

**Given Variables:**
- Percentage of ethanol by volume in beer: 6.50%
- Volume of the beer: 750.0 mL
- Density of ethanol: 0.789 g ethanol/mL ethanol

#### Detailed Steps:
1. **Determine Volume of Ethanol:**
    \[ \text{Volume of ethanol} = \text{Volume of beer} \times \left( \frac{\text{\% ethanol}}{100} \right) \]
    Where:
    - Volume of beer is 750.0 mL
    - Percentage of ethanol by volume is 6.50%
    - Hence, Volume of ethanol is \( 750.0 \, \text{mL} \times \left( \frac{6.50}{100} \right) = 48.75 \, \text{mL ethanol} \)

2. **Convert Volume of Ethanol to Mass of Ethanol:**
    \[ \text{Mass of ethanol} = \text{Volume of ethanol} \times \text{Density of ethanol} \]
    - Volume of ethanol is 48.75 mL
    - Density of ethanol is 0.789 g/mL
    - Hence,  Mass of ethanol is \( 48.75 \, \text{mL ethanol} \times 0.789 \, \text{g/mL} \)

3. **Calculation:**
    \[ \text{Mass of ethanol} = 48.75 \, \text{mL ethanol} \times 0.789 \, \text{g/mL} = 38.45 \, \text{g ethanol} \]

### Conclusion
Transcribed Image Text:### Problem Statement A particular beer is **6.50 % ethanol by volume (C₂H₆O)**. If a single bottle of beer contains **750.0 mL of beer**, what mass, in **g of ethanol (C₂H₆O)**, is present in the bottle? The density of ethanol is **0.789 g ethanol/mL ethanol**. ### Diagram Explanation #### Equation Setup: The diagram helps set up the calculation as follows: **Starting Amount:** - Initial volume of beer available, given as 750.0 mL. **Calculation Formula:** The diagram provides a structure to solve the problem step-by-step visually, using multiplication and unit conversions. **Given Variables:** - Percentage of ethanol by volume in beer: 6.50% - Volume of the beer: 750.0 mL - Density of ethanol: 0.789 g ethanol/mL ethanol #### Detailed Steps: 1. **Determine Volume of Ethanol:** \[ \text{Volume of ethanol} = \text{Volume of beer} \times \left( \frac{\text{\% ethanol}}{100} \right) \] Where: - Volume of beer is 750.0 mL - Percentage of ethanol by volume is 6.50% - Hence, Volume of ethanol is \( 750.0 \, \text{mL} \times \left( \frac{6.50}{100} \right) = 48.75 \, \text{mL ethanol} \) 2. **Convert Volume of Ethanol to Mass of Ethanol:** \[ \text{Mass of ethanol} = \text{Volume of ethanol} \times \text{Density of ethanol} \] - Volume of ethanol is 48.75 mL - Density of ethanol is 0.789 g/mL - Hence, Mass of ethanol is \( 48.75 \, \text{mL ethanol} \times 0.789 \, \text{g/mL} \) 3. **Calculation:** \[ \text{Mass of ethanol} = 48.75 \, \text{mL ethanol} \times 0.789 \, \text{g/mL} = 38.45 \, \text{g ethanol} \] ### Conclusion
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