How many milliliters of 0.592 M KOH are needed to react completely with 55.0 mL of 0.271 M FeCl2 solution to precipitate Fe(OH)2? The net ionic equation is: Fe2*(aq) + 20H (aq) → Fe(OH)2(s) VKOH = i ! ml

How many milliliters of 0.592 M KOH are needed to react completely with 55.0 mL of 0.271 M FeCl2 solution to precipitate Fe(OH)2? The net ionic equation is: Fe2*(aq) + 20H (aq) → Fe(OH)2(s) VKOH = i ! ml

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Related questions

Q: The metathesis reaction between iron (III) nitrate and potassium hydroxide is shown below Fe(NO3)3…

Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.700 M Zn(NO:)2 reacts with 17.5 mL of…

Q: What volume (in mL) of 0.0152 M HBr solution is required to titrate 125 mL of a 0.0132 M Ca(OH)2…

A: Here we are using mole concept method. We can also use equivalent method (by equating their…

Q: 0.7532 g of copper turnings (molar mass: 63.546 g∙mol–1) are reacted with excess nitric acid.…

A: Disclaimer: In order to obtain copper sulfate the acid used in excess should be sulfuric acid and…

Q: Aqueous barium chloride reacts with aqueous sodium sulfate in a double replacement reaction that…

Q: Consider the reaction: CaCl2(aq) + 2A9NO3(aq) → Ca(NO3)2(aq) + 2A9CI(s) How many grams of CaCl,…

A: Welcome to bartleby !

Q: If 33.0 g of NaOH is added to 0.650 L of 1.00 M Cu(NO₃)₂, how many grams of Cu(OH)₂ will be formed…

A: First of all, converting everything into the number of moles will help us to find the limiting…

Q: 50.0 mL of a 1.25 M solution of nitric acid is added to 1.12 g of solid iron(III) hydroxide, what is…

A: 50.0 mL of a 1.25 M solution of nitric acid is added to 1.12 g of solid iron(III) hydroxide, the…

Q: What mass of NaCl is required to precipitate all the silver ions from 30.0 mL of 0.355 M AgNO3…

A: We will use simple mole concept. however, we have to know the following formulas- Molarity=Number of…

Q: What volume of 0.874 M HCI, in milliliters, is required to titrate 1.30 g of NaOH to the equivalence…

A: Number of moles = 1.30 g / 40g mol-1 = 0.0325 mol At equivalence point Moles of HCl = Moles of NaOH

Q: If 30.5 g of NaOH is added to 0.550 L of 1.00 M Ni(NO₃)₂, how many grams of Ni(OH)₂ will be formed…

A: Answer: Mass of Ni(OH)2 precipitated = 35.3 g (rounded off to three significant…

Q: What mass of precipitate (in g) is formed when 250.0 mL of 0.200 M CoCl₂ is mixed with excess KOH in…

A: The balanced equation is given as; CoCl2(aq) + 2 KOH (aq)→Co(OH)2(s)+2KCl(aq) From the question,…

Q: Complete a reaction table (in millimoles) for the net reaction resulting when 41.4 mL of 0.0830 M…

A: A question based on mole concept. A set of data for a balanced equation is given based on which the…

Q: If 19.5 g of NaOH is added to 0.800 L of 1.00 M Zn(NO₃)₂, how many grams of Zn(OH)₂ will be formed…

A: Given, Mass of NaOH = 19.5 g Molarity of Zn(NO₃)₂ = 1.00 M Volume of Zn(NO₃)₂…

Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.700 M Zn(NO₃)₂ reacts with 23.0 mL of…

A: Number of moles of substance=Concentration of substance x Volume of substanceFor…

Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.500 M Cu(NO3)2 reacts with 20.0 mL of…

A: Here we are required to find the mass of precipitate formed during the given reaction 1L=1000 ml.

Q: Concentration of calcium in a sample may be determined by precipitation using the chromate ion,…

Q: 150.0 mL of 0.200 M AgNO3 solution is reacted with 100.0 mL of 0.450 M NaBr solution, and the…

A: The balanced reaction taking place is given as, => AgNO3 (aq) + NaBr (aq) -----> AgBr (s) +…

Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.700 M Zn(NO₃)₂ reacts with 31.0 mL of…

A: ZnNO32+2 NaOH→ZnOH2 s+2 NaNO3 aqStength of ZnNO32=20.5x0.700 M1000=0.0143Stength of NaOH=310x0.700…

Q: Concentration of calcium in a sample may be determined by precipitation using the chromate ion,…

Q: Calculate the number of milliliters of 0.674 M Ba(OH)2 required to precipitate all of the Al3+ ions…

A: Given, Molarity of Ba(OH)2 solution = 0.674 M = 0.674 mol/L Volume of AlI3 solution = 190 mL = 0.190…

Q: Consider the reaction: Li,S(ag) + Co(NO3)2(ag) → 2 LİNO,(aq) + CoS(s) What volume of 0.150 M LiS…

A: The equation to calculate the unknown values from known ones are given by M1V1=M2V2 where M is the…

Q: If 27.70 mL of 0.138 M barium hydroxide is required to neutralize 23.0 mL of nitrous acid, what is…

Q: If 34.5 g of NaOH is added to 0.600 L of 1.00 M Mn(NO₃)₂, how many grams of Mn(OH)₂ will be formed…

A: We will use stoichiometry of the reaction to get the answer

Q: To measure the amount of chlorine in a well-boring fluid, an analytical chemist adds 0.180M silver…

Q: How many grams of Cu(OH)2 will precipitate when excess NaOH solution is added to 59.0 mL of 0.615 M…

Q: The concentration of Sn²+ in a solution is determined by titrating it with a 0.1798 M Ce¹+ solution.…

A: Answer:- This question is answered by using the simple concept of stoichiometry which involves the…

Q: 23.0 g of NaOH is added to 0.600 L of 1.00 M Mn(NO₃)₂, how many grams of Mn(OH)₂ will be formed in…

A: 1- Moles of NaOH = ( mass / molar mass) Moles of NaOH = ( 23.0g / 40gmol-1 ) Moles of NaOH = 0.575…

Q: Generally, only the carbonates of the Group 1 elements and the ammonium ion are soluble in water;…

A: Calcium chloride reacts with sodium carbonate to get calcium carbonate. Molarity = moles/volume of…

Q: Calculate the number of milliliters of 0.616 M Ba(OH), required to precipitate all of the Cu2+ ions…

A: Copper sulfate reacts with barium hydroxide to form precipitates of copper hydroxide and an aqueous…

Q: If 26.0 g of NaOH is added to 0.600 L of 1.00 M Mn(NO₃)₂, how many grams of Mn(OH)₂ will be formed…

A: The balanced reaction taking place is given as, => 2 NaOH(aq) + Mn(NO₃)₂(aq) → Mn(OH)₂ (s) + 2…

Q: According to the following reaction, how many moles of Fe(OH)2 can form from complete reaction of…

A: Molarity of LiOH solution = 0.454 M = 0.454 mol L-1…

Q: If 29.5 g of NaOH is added to 0.700 L of 1.00 M Co(NO3)2, how many grams of Co(OH)2 will be formed…

A: Given : Mass of NaOH = 29.5 gm Concentration of Co(NO3)2 = 1.00 M Volume of Co(NO3)2 solution =…

Q: How many moles of precipitate will be formed when 100 mL of 2.00 M NaBr is reacted with 70.0 mL of…

A: The mole of precipitate will be formed has to be determined

Q: In a precipitation reaction between FeCl2(aq) and LiOH(aq), 109ml of 0.18 M FeCl2(aq) completely…

Q: 5. What is the concentration of NaCl in a solution if titration of 15.00 mL of the solution with…

A: Molarity of a solution is equal to the number of solute present in one litre of solution. Write the…

Q: if 30.0 g of NaOH is added to 0.800L of 1.00M Zn(NO3)2, what is the mass in grams of Zn(OH)2 will…

A: The balanced equation for the given precipitation reaction is as follows.…

Q: If 28.0 g of NaOH is added to 0.550 L of 1.00 M Ni(NO₃)₂, how many grams of Ni(OH)₂ will be formed…

A: In the reaction ; 2 NaOH(aq) + Ni(NO₃)₂(aq) → Ni(OH)₂ (s) + 2 NaNO₃ (aq) So, we can conclude that 2…

Q: How many grams of Cu(OH)2 will precipitate when excess NaOH solution is added to 72.0 mL of 0.578 M…

Q: If 25.5 g of NaOH is added to 0.550 L of 1.00 M Ni(NO₃)₂, how many grams of Ni(OH)₂ will be formed…

Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.400 M Mn(NO₃)₂ reacts with 32.0 mL of…

Q: How many grams of cobalt(II) chloride are needed to react completely with 30.7 mL of 0.324 M KOH…

A: this is a type of double displacement reaction in which ions of both the salts are getting…

Q: Calculate the number of milliliters of 0.650 M NaOH required to precipitate all of the Zn2+ ions in…

A: Given : Zn(NO3)2(aq) + 2NaOH(aq) Zn(OH)2(s) + 2NaNO3(aq) Molarity of NaOH solution = 0.650 M or…

Q: If 32.5 g of NaOH is added to 0.550 L of 1.00 M Ni(NO₃)₂, how many grams of Ni(OH)₂ will be formed…

A: The reaction considered is, 2 NaOH(aq)+Ni(NO3)2(aq)→Ni(OH)2 (s)+ 2 NaNO3(aq)

Q: If 16.5 g of NaOH is added to 0.550 L of 1.00 M Ni(NO₃)₂, how many grams of Ni(OH)₂ will be formed…

A: The balanced reaction given is 2 NaOH(aq) + Ni(NO₃)₂(aq) → Ni(OH)₂ (s) + 2 NaNO₃ (aq) Given : Mass…

Question

How many milliliters of 0.592 M KOH are needed to react completely with 55.0 mL of 0.271 M FeCl2 solution to precipitate Fe(OH)2?
The net ionic equation is:
Fe2*(aq) + 20H (aq) → Fe(OH)2(s)
VKOH =
i
! mL
eTextbook and Media
Hint
Attempts: 3 of 15 used
Submit Answer
Save for Later
ост
tv
15
MacBook Air
DII
DD
F9
888
80
F5
F4
F3
F2
&
@
#
$
7
8
6.
2
3
4

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Similar questions

How many grams of PbBr2 will precipitate when excess NiBr2 solution is added to 47.0 mL of 0.602 M Pb(NO3)2 solution? Pb(NO3)2 (aq) + NiBr2 (aq) → PbBr2 (s) + Ni(NO3)2 (aq) g
How many grams of Cu(OH)2 will precipitate when excess NaOH solution is added to 60.0 mL of 0.684 M CuBr2 solution? CuBr₂ (aq) + 2NaOH(aq) → Cu(OH)2 (s) + 2NaBr(aq) g
Calculate the number of milliliters of 0.479 M Ba(OH)2 required to precipitate all of the Cr³+ ions in 156 mL of 0.725 M CrIs solution as Cr(OH)3. The equation for the reaction is: 2Crls (aq) + 3Ba(OH)2 (aq) → 2Cr(OH)s (8) + 3Bal, (aq) ml. Volume= Submit Answer Retry Entire Group 9 more group attempts remaining
Calculate the number of milliliters of 0.581 M NAOH required to precipitate all of the Cu* ions in 128 mL of 0.452 M CuSO, solution as Cu(OH)2. The equation for the reaction is: Cuso (aq) + 2N2OH(aq) Cu(OH)2(s)+ NazsO,(aq) mL NAOH
If 785 mL of 0.350 M AgNO₃ is added to 475 mL of 0.250 M CaBr₂, how many moles of AgBr precipitate will be formed? The balanced equation is 2 AgNO₃(aq) + CaBr₂(aq) → 2 AgBr(s) + Ca(NO₃)₂(aq)
Lead(II) ions can be precipitated out of solution through the following reaction: Pb(NO3)2 (aq) +2 NaOH (aq)→Pb(OH)2 (s) +2 NaNO3 (aq) What volume of a 3.50 M NaOH solution is required to completely react with 750. mL of 1.20 M Pb(NO3)2
Calculate the number of milliliters of 0.580 M Ba(OH)2 required to precipitate all of the Cu2+ ions in 120 mL of 0.745 M CuCl2 solution as Cu(OH)2. The equation for the reaction is:CuCl2(aq) + Ba(OH)2(aq) Cu(OH)2(s) + BaCl2(aq) mL Ba(OH)2
How many grams of Ba(NO3)2 are required to precipitate all the sulfate ion present in 14.1 mL of 0.182 M H2SO4 solution? Ba(NO3)2(aq) + H2SO4(aq) → BaSO4(s) + 2 HNO3(aq)
Calculate the number of milliliters of 0.564 M sodium hydroxide required to precipitate all of the Cu2+ ions in 107 mL of 0.56 M copper (II) nitrate solution as copper (II) hydroxide. The reaction proceeds as follows: copper (II) nitrate (aq) + sodium hydroxide (aq) → copper (II) hydroxide (s) + sodium nitrate (aq)
You wish to quantify the amount of Mg(OH), in an antacid suspension. You titrate the antacid with hydrochloric acid, according to the reaction shown here. 2HCI(aq) + Mg(OH)2 (aq) → 2H20(1) + MgCl2(aq) If you completely react 25.0 mL of the antacid suspension with 20.0 mL of 1.00 M HCI, what is the molar concentration of Mg(OH), in the antacid suspension? O 0.0800 M O 0.0200 M 0.400 M 0.600 M
What volume in mL of 0.45 M HBr solution is required to titrate 125mL of a 0.21 M Ca(OH)2 solution? Ca(OH)2(aq) + 2HBr(aq) -> CaBr2(aq) + 2H2O(I)
If 28.0 g of NaOH is added to 0.600 L of 1.00 M Mn(NO₃)₂, how many grams of Mn(OH)₂ will be formed in the following precipitation reaction? 2 NaOH(aq) + Mn(NO₃)₂(aq) → Mn(OH)₂ (s) + 2 NaNO₃(aq)