What mass of NaCl is required to precipitate all the silver ions from 30.0 mL of 0.355 M AgNO3 solution? NaCl (ag) + AgNO3 (ag) -> NaNO3 (ag) + AgCl (s)

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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What mass of NaCl is required to precipitate all the silver ions from 30.0 mL of 0.355 M AgNO3
solution?
NaCl (aq) + AgNO3(aq) -> NaNO3 (ag) + AgCl (s)
For the reaction
CuSO4 (ag) + 2 NaOH (ag) ——> Cu(OH)2 (s) + Na₂SO4 (ag)
How many mL of 0.150 M NaOH are required to react with 30.0 mL of 0.250 M CuSO4?
Transcribed Image Text:What mass of NaCl is required to precipitate all the silver ions from 30.0 mL of 0.355 M AgNO3 solution? NaCl (aq) + AgNO3(aq) -> NaNO3 (ag) + AgCl (s) For the reaction CuSO4 (ag) + 2 NaOH (ag) ——> Cu(OH)2 (s) + Na₂SO4 (ag) How many mL of 0.150 M NaOH are required to react with 30.0 mL of 0.250 M CuSO4?
Expert Solution
Step 1

We will use simple mole concept. however, we have to know the following formulas-

Molarity=Number of molesVolume in litersNumber of moles=MassMolar mass1liter=1000mL

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