What was the molarity of the KOH solution

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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A titration is a procedure for determining the
concentration of a solution by allowing it to react with
another solution of known concentration (called a
standard solution). Acid-base reactions and
oxidation-reduction reactions are used in titrations.
For example, to find the concentration of an HCI
solution (an acid), a standard solution of NaOH (a
base) is added to a measured volume of HCl from a
calibrated tube called a buret. An indicator is also
present and it will change color when all the acid has
reacted. Using the concentration of the standard
solution and the volume dispensed, we can calculate
molarity of the HCl solution.
Part A
A volume of 70.0 mL of aqueous potassium hydroxide (KOH) was titrated against a standard solution of sulfuric acid (
H2SO4). What was the molarity of the KOH solution if 15.7 mL of 1.50 M H2SO4 was needed? The equation is
2KOH(aq) +H2SO4(aq)→K2SO4(aq) +2H2O(1)
Express your answer with the appropriate units.
> View Available Hint(s)
HẢ
?
molarity =
Value
Units
Transcribed Image Text:A titration is a procedure for determining the concentration of a solution by allowing it to react with another solution of known concentration (called a standard solution). Acid-base reactions and oxidation-reduction reactions are used in titrations. For example, to find the concentration of an HCI solution (an acid), a standard solution of NaOH (a base) is added to a measured volume of HCl from a calibrated tube called a buret. An indicator is also present and it will change color when all the acid has reacted. Using the concentration of the standard solution and the volume dispensed, we can calculate molarity of the HCl solution. Part A A volume of 70.0 mL of aqueous potassium hydroxide (KOH) was titrated against a standard solution of sulfuric acid ( H2SO4). What was the molarity of the KOH solution if 15.7 mL of 1.50 M H2SO4 was needed? The equation is 2KOH(aq) +H2SO4(aq)→K2SO4(aq) +2H2O(1) Express your answer with the appropriate units. > View Available Hint(s) HẢ ? molarity = Value Units
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