h Oxidation: Cr2+→ Cr³+ + e Reduction: Cu2+ + 2 e² → Cu Net: 2 Cr2+ + Cu2+ Cu + 2 Cr³+ What is the standard potential, Eºnet? Standard Reduction Potentials Reduction Half-Reaction E° (V) CO³+ +e- - Co²+ 1.82 Au³+ + 3e- → Au(s) Pd²+ + 2 e- → Pd Ag+ + e- Fe³+ + e- Cu++ e- Cu²++2 e- Cu²++ e- 2H+ + 2 e- Sn²+ + 2 e- Co²++2 e- Cr³+ + e- Fe²++2 e- Cr³++3 e- Zn²++2 e- A1³++ 3 e- Eºnet = V 1.50 0.987 Ag(s) 0.80 Fe2+ 0.771 → Cu(s) 0.52 → Cu(s) 0.337 → Cut 0.153 → H₂(g) 0.00 → Sn(s) -0.14 → Co(s) -0.28 →Cr²+ -0.41 →Fe(s) -0.44 → Cr(s) -0.74 → Zn(s) -0.763 →Al(s) -1.66

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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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h
Oxidation: Cr2+ → Cr³+ + e
Reduction: Cu²+ + 2 e¯ → Cu
Net: 2 Cr²+ + Cu²+
What is the standard potential, Eºnet ?
Standard Reduction Potentials
Eº net
Reduction Half-Reaction E° (V)
Co³+ + e-
→ Co²+ 1.82
Au³ + + 3e-
→ Au(s) 1.50
Pd²+ + 2 e-
→ Pd
0.987
Ag++ e-
→ Ag(s) 0.80
Fe³+ + e-
→ Fe²+ 0.771
→ Cu(s)
0.52
→ Cu(s) 0.337
→ Cut 0.153
→ H₂(g)
0.00
→ Sn(s)
-0.14
Cu++ e-
Cu²++2 e-
Cu²++ e-
2H+ + 2 e-
Sn²+ + 2 e-
Co²+ +2 e-
Cr³++ e-
Fe²+ +2 e-
Cr³+ +3 e-
Zn²++ 2 e-
A1³+ + 3 e-
→ Cu + 2 Cr³+
=
V
→Co(s)
-0.28
→ Cr²+ -0.41
→ Fe(s)
-0.44
→ Cr(s)
-0.74
→ Zn(s) -0.763
→Al(s) -1.66
Transcribed Image Text:h Oxidation: Cr2+ → Cr³+ + e Reduction: Cu²+ + 2 e¯ → Cu Net: 2 Cr²+ + Cu²+ What is the standard potential, Eºnet ? Standard Reduction Potentials Eº net Reduction Half-Reaction E° (V) Co³+ + e- → Co²+ 1.82 Au³ + + 3e- → Au(s) 1.50 Pd²+ + 2 e- → Pd 0.987 Ag++ e- → Ag(s) 0.80 Fe³+ + e- → Fe²+ 0.771 → Cu(s) 0.52 → Cu(s) 0.337 → Cut 0.153 → H₂(g) 0.00 → Sn(s) -0.14 Cu++ e- Cu²++2 e- Cu²++ e- 2H+ + 2 e- Sn²+ + 2 e- Co²+ +2 e- Cr³++ e- Fe²+ +2 e- Cr³+ +3 e- Zn²++ 2 e- A1³+ + 3 e- → Cu + 2 Cr³+ = V →Co(s) -0.28 → Cr²+ -0.41 → Fe(s) -0.44 → Cr(s) -0.74 → Zn(s) -0.763 →Al(s) -1.66
a. Cr³+ (aq) + Cl₂ (g) ⇒ Cr₂O7² (aq) + Cl¯(aq)
=
V
2+
b. Ni²+ (aq) + Ca(s) ⇒ Ca²+ (aq) + Ni(s)
V
Transcribed Image Text:a. Cr³+ (aq) + Cl₂ (g) ⇒ Cr₂O7² (aq) + Cl¯(aq) = V 2+ b. Ni²+ (aq) + Ca(s) ⇒ Ca²+ (aq) + Ni(s) V
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