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HO (c) (1 pt) Both of the following are hydride donors. Circle the harder nucleophile of -P-Cu-H H + H-AI-H H (d) (4 pts) The following reaction involves two steps. Draw the anionic intermediate that forms after sodium hydride reacts and the final organic product. Hints: what type of nucleophile is NaH and where does that mean it will react? Also, the second step is not a proton transfer. What's the most likely reaction for that intermediate to undergo? NaH anionic intermediate final product

HO (c) (1 pt) Both of the following are hydride donors. Circle the harder nucleophile of -P-Cu-H H + H-AI-H H (d) (4 pts) The following reaction involves two steps. Draw the anionic intermediate that forms after sodium hydride reacts and the final organic product. Hints: what type of nucleophile is NaH and where does that mean it will react? Also, the second step is not a proton transfer. What's the most likely reaction for that intermediate to undergo? NaH anionic intermediate final product

Organic Chemistry: A Guided Inquiry
Organic Chemistry: A Guided Inquiry
2nd Edition
ISBN:9780618974122
Author:Andrei Straumanis
Publisher:Andrei Straumanis
Chapter20: Acidity And Pka Of Phenols
Section: Chapter Questions
Problem 11E
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HO (c) (1 pt) Both of the following are hydride donors. Circle the harder nucleophile of -P-Cu-H H + H-AI-H H (d) (4 pts) The following reaction involves two steps. Draw the anionic intermediate that forms after sodium hydride reacts and the final organic product. Hints: what type of nucleophile is NaH and where does that mean it will react? Also, the second step is not a proton transfer. What's the most likely reaction for that intermediate to undergo? NaH anionic intermediate final product
Transcribed Image Text:HO (c) (1 pt) Both of the following are hydride donors. Circle the harder nucleophile of -P-Cu-H H + H-AI-H H (d) (4 pts) The following reaction involves two steps. Draw the anionic intermediate that forms after sodium hydride reacts and the final organic product. Hints: what type of nucleophile is NaH and where does that mean it will react? Also, the second step is not a proton transfer. What's the most likely reaction for that intermediate to undergo? NaH anionic intermediate final product
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