Heroin (molar mass = 359 g/mol) is also a narcotic drug and is a derivative of morphine. How many heroin molecules are present in 3.25 mols of heroin? A. 19.565 x 1023 molecules B. 1.956 x 1024 molecules O C. 2.00 x 1024 molecules D. 1.96 x 1024 molecules O E. 1170 molecules
Heroin (molar mass = 359 g/mol) is also a narcotic drug and is a derivative of morphine. How many heroin molecules are present in 3.25 mols of heroin? A. 19.565 x 1023 molecules B. 1.956 x 1024 molecules O C. 2.00 x 1024 molecules D. 1.96 x 1024 molecules O E. 1170 molecules
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Problem Statement:**
Heroin (molar mass = 359 g/mol) is also a narcotic drug and is a derivative of morphine. How many heroin molecules are present in 3.25 mols of heroin?
**Multiple Choice Options:**
A. \(19.565 \times 10^{23}\) molecules
B. \(1.956 \times 10^{24}\) molecules
C. \(2.00 \times 10^{24}\) molecules
D. \(1.96 \times 10^{24}\) molecules
E. 1170 molecules
**Explanation:**
To find the number of molecules in a given number of moles, use Avogadro's number: \(6.022 \times 10^{23}\) molecules/mol.
1. Multiply the number of moles of heroin (3.25 mols) by Avogadro’s number:
\[
3.25 \, \text{mol} \times 6.022 \times 10^{23} \, \text{molecules/mol} = 1.956 \times 10^{24} \, \text{molecules}
\]
2. Therefore, the correct answer is B. \(1.956 \times 10^{24}\) molecules.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd5770d38-7bc6-4305-a1b7-fd2f8a59c389%2F4b3255a6-7b38-42ff-8e60-e1526f95aa28%2Fbk5ytpf_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
Heroin (molar mass = 359 g/mol) is also a narcotic drug and is a derivative of morphine. How many heroin molecules are present in 3.25 mols of heroin?
**Multiple Choice Options:**
A. \(19.565 \times 10^{23}\) molecules
B. \(1.956 \times 10^{24}\) molecules
C. \(2.00 \times 10^{24}\) molecules
D. \(1.96 \times 10^{24}\) molecules
E. 1170 molecules
**Explanation:**
To find the number of molecules in a given number of moles, use Avogadro's number: \(6.022 \times 10^{23}\) molecules/mol.
1. Multiply the number of moles of heroin (3.25 mols) by Avogadro’s number:
\[
3.25 \, \text{mol} \times 6.022 \times 10^{23} \, \text{molecules/mol} = 1.956 \times 10^{24} \, \text{molecules}
\]
2. Therefore, the correct answer is B. \(1.956 \times 10^{24}\) molecules.
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