Hello, I had asked the following multi-part question in pieces because there are several different parts to this question, but each tutor is giving me a different answer, so I wanted to compare for the last time and put what each tutor put for the following for this question, as I am confused. Thank you for your time! 1-3) for the pictorial, the truck is driving towards the right, and is on a point of (0,0) while the pothole is to the right at (0,20). There is force going towards the left at -5.625 m/s2 4) Unfortunately, I was not given the three step process. I was left with the equation O^2- U^2 = 2 ad, solved for "a", and got the answer -5.625 m/s^2 5) for assumption of no sliding fo rthe crate, it was solved to be 3.92 m/s^2, and it was determined that the crate would not slide, but I'm not entirely sure how to draw the motion diagram. 6) Force on crate was found to be 3.92 7) f(max)/f(required)=3.92/-5.625=-0.697. I am unsure if this is supposed to be a positive or negative value.
Displacement, Velocity and Acceleration
In classical mechanics, kinematics deals with the motion of a particle. It deals only with the position, velocity, acceleration, and displacement of a particle. It has no concern about the source of motion.
Linear Displacement
The term "displacement" refers to when something shifts away from its original "location," and "linear" refers to a straight line. As a result, “Linear Displacement” can be described as the movement of an object in a straight line along a single axis, for example, from side to side or up and down. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Linear displacement is usually measured in millimeters or inches and may be positive or negative.
Hello,
I had asked the following multi-part question in pieces because there are several different parts to this question, but each tutor is giving me a different answer, so I wanted to compare for the last time and put what each tutor put for the following for this question, as I am confused. Thank you for your time!
1-3) for the pictorial, the truck is driving towards the right, and is on a point of (0,0) while the pothole is to the right at (0,20). There is force going towards the left at -5.625 m/s2
4) Unfortunately, I was not given the three step process. I was left with the equation O^2- U^2 = 2 ad, solved for "a", and got the answer -5.625 m/s^2
5) for assumption of no sliding fo rthe crate, it was solved to be 3.92 m/s^2, and it was determined that the crate would not slide, but I'm not entirely sure how to draw the motion diagram.
6) Force on crate was found to be 3.92
7) f(max)/f(required)=3.92/-5.625=-0.697. I am unsure if this is supposed to be a positive or negative value.
Trending now
This is a popular solution!
Step by step
Solved in 4 steps with 1 images
