In the diagram below a ship is approaching a tower at 1.5m/s. For the ship to dock, a piece of equipment must be thrown to the ship from the tower. The equipment will be thrown at 600 above the horizontal at 15m/s from the tower. The tower is 8.75m above the ship. a) What horizontal distance away from the light tower should the ship be when the equipment is thrown from the tower so the ship can catch the equipment? b) What is the horizontal and vertical velocity when the equipment lands relative to the boat?

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In the diagram below a ship is approaching a tower at 1.5m/s. For the ship to dock, a piece of equipment must be thrown to the ship from the tower. The equipment will be thrown at 600 above the horizontal at 15m/s from the tower. The tower is 8.75m above the ship. a) What horizontal distance away from the light tower should the ship be when the equipment is thrown from the tower so the ship can catch the equipment? b) What is the horizontal and vertical velocity when the equipment lands relative to the boat?

15 m/s
60°
tower
ship
distance
Transcribed Image Text:15 m/s 60° tower ship distance
Expert Solution
Step 1

Given data: 

Height of the tower above the ship, dy=8.75 m

Speed of the equipment u=15 ms-1

Speed of the boat v'=1.5 ms-1

The angle at which equipment is thrown with the horizontal, θ=60C

 

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