Hello I am trying to solve this loads and reactive forces problem 1.7. I'm having a difficult time understanding how the distributed load is for I2 = 3ft and I3= 1 ft where did they get 3ft and 1 ft. I understand how they got I1= 7ft with a beam spaning 14 ft divide 2 = 7ft and I wondering where they got these two answer for I2 = 3ft and I3= 1 ft ?
Hello I am trying to solve this loads and reactive forces problem 1.7. I'm having a difficult time understanding how the distributed load is for I2 = 3ft and I3= 1 ft where did they get 3ft and 1 ft. I understand how they got I1= 7ft with a beam spaning 14 ft divide 2 = 7ft and I wondering where they got these two answer for I2 = 3ft and I3= 1 ft ?
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
Hello I am trying to solve this loads and reactive forces problem 1.7. I'm having a difficult time understanding how the distributed load is for I2 = 3ft and I3= 1 ft where did they get 3ft and 1 ft. I understand how they got I1= 7ft with a beam spaning 14 ft divide 2 = 7ft and I wondering where they got these two answer for I2 = 3ft and I3= 1 ft ?
![Given information:
The total length of the beam is 14 ft (4.2 m).
The downward load P, acting at 3 ft from the right support is 4,000
Ib (17.8 kN).
The uniformly distributed load wi is 6,000 lb (26.7 kN) acting
throughout the span.
The uniformly distributed load wz is 2,000 lb (8.90 kN) acting along
8 ft from the right support.
Calculation:
Show the given beam as in Figure (1).
2,000 lb
4,000 lb (17.8 kN)
6,000 lb
(8.90 kN)
(26.7 kN)
6 ft (1.8 m)
5 ft (1.5 m)
3 ft (0.9 m)
L= 14 ft (4.2 m)
R1
R2
Figure 1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffeb710f9-5b43-4ced-a801-b89c99bfcf7c%2F0e1ff50a-c0a3-4da1-965b-90273bb3c23a%2Ftwx3vll_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Given information:
The total length of the beam is 14 ft (4.2 m).
The downward load P, acting at 3 ft from the right support is 4,000
Ib (17.8 kN).
The uniformly distributed load wi is 6,000 lb (26.7 kN) acting
throughout the span.
The uniformly distributed load wz is 2,000 lb (8.90 kN) acting along
8 ft from the right support.
Calculation:
Show the given beam as in Figure (1).
2,000 lb
4,000 lb (17.8 kN)
6,000 lb
(8.90 kN)
(26.7 kN)
6 ft (1.8 m)
5 ft (1.5 m)
3 ft (0.9 m)
L= 14 ft (4.2 m)
R1
R2
Figure 1
![W2 = 2,000 lb
(8.90 kN)
W = 6,000 lb
(26.7 kN)
P = 4,000 lb (17.8 kN)
1 =7 ft (2.1 m)
2= 3 ft
4 = 3 ft
(0.9 m) =1 ft (0.9 m)
R2
R1
(0.3 m)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffeb710f9-5b43-4ced-a801-b89c99bfcf7c%2F0e1ff50a-c0a3-4da1-965b-90273bb3c23a%2Flpxnab_processed.jpeg&w=3840&q=75)
Transcribed Image Text:W2 = 2,000 lb
(8.90 kN)
W = 6,000 lb
(26.7 kN)
P = 4,000 lb (17.8 kN)
1 =7 ft (2.1 m)
2= 3 ft
4 = 3 ft
(0.9 m) =1 ft (0.9 m)
R2
R1
(0.3 m)
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