Consider the same beam as in Problem 1. It carries a live load of 3 kips/ft.8" 8"V (kips)wlM (kips)9w/²1286"6 #67.5 ft.7.5 ft.AWL =3 kips/ft.1 =20 ft.6 #950085 ft.Bwl8-W/2B 2.5"10"6 #6la20"=Section A-A5"22"2.5"6 #96#6Section B-BThe beam is simply supported at the left end and fixed at the right end. Under a unform loadw, it has the shear and moment diagrams shown above. It has normal weight concrete. Theconcrete strength is specified to be 4,000 psi and the steel is Grade 60. The amount ofreinforcement satisfies the tension-controlled condition.I 4”In addition to its own weight, it carries a live of 3 kips/ft. The live load is imposed on the topof the web of the beam. Solve the following partsThe 6#6 bars at the bottom extend along the entire length of the beam. All the 6#9bars are to be terminated together at the point it is no long required according to thespecification of ACI 318. Determine the distance of the termination point fromthe face of the right support. Check if the development length requirement ofACI 318 is satisfied. For this check, you may use the simplified formula in ACI318:fyy.=d, where x = 20 for #7 and larger bars, x = 25 for #6 and smaller barsx√fi

Given: Section A-A: 6-#6 rebar = 0.75 in Section B-B: 6-#9 rebar = 1.128 in Development length = 6…

The 6#6 bars at the bottom extend along the entire length of the beam. All the 6#9 bars are to be terminated together at the point it is no long required according to the specification of ACI 318. Determine the distance of the termination point from the face of the right support. Check if the development length requirement of ACI 318 is satisfied. For this check, you may use the simplified formula in ACI 318:

The 6#6 bars at the bottom extend along the entire length of the beam. All the 6#9 bars are to be terminated together at the point it is no long required according to the specification of ACI 318. Determine the distance of the termination point from the face of the right support. Check if the development length requirement of ACI 318 is satisfied. For this check, you may use the simplified formula in ACI 318:

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Problem 20. The member shown is part of a braced frame. Bending is about the x-axis and the steel is ASTM A992. For the member shown, the factor Cm that will be used to compute the amplification factor is 0.2 0.4 0.6 1.0 21. For the member shown in problem 20, using ASD, compute the moment amplification factor B1. a 1.0 b 1.04 c 1.07 d 1.09
A column is formed by welding two A36 MC sections back-to- back. The column is 32 feet long. With respect to x-axis buckling, supports are hinged at the top, and fixed at the bottom. With respect to y-axis buckling, supports are pinned at both ends. Additionally, hinge supports are provided at the mid-height perpendicular to both axes. Use the recommended k-values. Below are the properties of a single MC section: A=6.45 in2, d=10 in, bf-3.32 in, x=0.990 in, Ix=102 in¹, ly=6.40 in, rx-3.99 in, ry=0.997 in
A mild steel bar is in two parts having equal lengths. The area of cross-section of Part-l is double that of Part-2. If the bar carries an axial load 'P', then the ratio of elongation in Part-I to that in Part-2 will be
Use A992 steel and select the lightest W shape. Use any design procedure.a. Use LRFD.b. Use ASD.
PROBLEM 2. The lap joint in the figure is made using a 30 mm diameter bolt. The outer plates are 5 mm thick, made of 2014- T6 aluminum and the inner plate is 10 mm thick and made of 6061-T6 aluminum. The bolt is made of S355 steel material. Calculate the load P that the lap joint can safely support, taking into account the failure of the plates by shear and tension and failure of the bolt by bearing and shear. Use a factor of safety for ultimate strength of F.S.=1.5 100 min 20 m P/2 P/2
please solve part 4.3
A steel plate (called a cover plate) having cross-sectional dimensions W2 8.0 in. x 0.7 in. is welded along the full length of the bottom flange of a W, 12.0 in. x 14.0 in. wide-flange beam (see the figure, which shows the beam cross section). I W2 cover plate What is the percent increase in the smaller section modulus (as compared to the wide-flange beam alone)? Round your answer to two decimal places. % in smaller section modulus =|
How to solve this question step by step
please solve part 4.1
only HANDWRITTEN answer needed ( NOT TYPED)
Analysis of frames/Zero force identification please show complete solution
The rigid frame shown in Figure is unbraced in the plane of the frame. In the direction perpendicular to the frame, the frame is braced at the joints. The connections at these points of bracing are simple (moment-free) connections. Roof girders are W14 x 30, and floor girders are W16 x 36. Member BC is a W10 x 45. Use A992 steel and select a W-shape for AB. Assume that the controlling load combination causes no moment in AB. The service dead load is 25 kips and the service live load is 75 kips. a. Use LRFD. b. Use ASD