he mean family income for a random sample of 700 suburban households in Guinesstowne shows that a 90 percent confidence interval is ($47,250, $62,100). Herman is conducting a test of the null hypothesis H0: µ = 45,000 against the alternative hypothesis Ha: µ ≠ 45,000 at the α = 0.10 level of significance. Does Herman have enough information to conduct a test of the null hypothesis against the alternative? Group of answer choices Yes, because $45,000 is not contained in the 90% confidence interval, the null hypothesis would not be rejected, and it could be concluded that the mean family income is not significantly different from $45,000 at the α = 0.10 level   Yes, because $45,000 is not contained in the 90% confidence interval, the null hypothesis would be rejected in favor of the alternative, and it could be concluded that the mean family income is significantly different from $45,000 at the α = 0.10 level   No, because the value of σ is not known   No, because it is not known whether the data are Normally distributed   No, because the entire data set is needed to do this test

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Author:Amos Gilat
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The mean family income for a random sample of 700 suburban households in Guinesstowne shows that a 90 percent confidence interval is ($47,250, $62,100). Herman is conducting a test of the null hypothesis H0: µ = 45,000 against the alternative hypothesis Ha: µ ≠ 45,000 at the α = 0.10 level of significance. Does Herman have enough information to conduct a test of the null hypothesis against the alternative?

Group of answer choices
Yes, because $45,000 is not contained in the 90% confidence interval, the null hypothesis would not be rejected, and it could be concluded that the mean family income is not significantly different from $45,000 at the α = 0.10 level
 
Yes, because $45,000 is not contained in the 90% confidence interval, the null hypothesis would be rejected in favor of the alternative, and it could be concluded that the mean family income is significantly different from $45,000 at the α = 0.10 level
 
No, because the value of σ is not known
 
No, because it is not known whether the data are Normally distributed
 
No, because the entire data set is needed to do this test
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