The image displays a chemical reaction that involves the formation of two different products from a common reactant. The instructions state: "The following reactions give two different products. Show the mechanisms leading to their formation."### Reaction Details:1. **First Reaction:** - Reactant: A cyclohexanone derivative (five-membered ring with a ketone group). - Reagents: Methanol (CH₃OH) and a proton source (H⁺). - Product: An acetal of the starting material with methanol, indicated by the addition of methoxy (-OCH₃) and hydroxyl groups (OH).2. **Second Reaction:** - Reactant: Same cyclohexanone derivative. - Reagents: Methoxide ion (CH₃O⁻) and methanol (CH₃OH). - Product: An ether formation is shown, where methoxy groups are added to the original structure.### Reaction Mechanisms:- **Mechanism for First Reaction:** - The acidic conditions suggest a standard acetal formation mechanism where the ketone undergoes protonation leading to a more reactive electrophilic center. Methanol then attacks, forming a hemiketal, followed by further reaction to form the acetal with the release of water.- **Mechanism for Second Reaction:** - The use of methoxide as a nucleophile under basic conditions indicates a nucleophilic attack on the carbonyl carbon. This often proceeds through a single step in basic conditions to quickly form ether linkages by direct displacement of the leaving group.These reactions illustrate the different pathways a single reactant can undergo based on the nature of the catalytic environment—acidic or basic catalyst—leading to bifurcation in the reaction pathway and formation of structurally different products.

As CH3OH is weak nucleophile and CH3O- is strong nucleophile In first reaction the reaction takes…

Answered: he following reactions give two…

he following reactions give two different products. Show the mechanisms leading to their formation. OH CH,OH CH,0 но CH,0 CH,OH OCH,

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Alcohols are acidic in nature. Therefore, a strong base can abstract the acidic hydrogen atom of the alcohol in a process known as deprotonation. The alcohol forms an alkoxide ion by losing the proton attached to the oxygen atom of the hydroxyl ( -OH) group. The alkoxide formed can act as a base or a nucleophile depending on the substrate and reaction conditions. However, not all bases can abstract the acidic proton of alcohols and not all alcohols easily lose the proton. Deprotonation depends on the strength of the base and the acidity of the alcohol. Strong bases, such as NaNH2, can easily abstract a proton from almost all alcohols. Likewise, more acidic alcohols lose a proton more easily. Determine which of the following reactions would undergo deprotonation based on the strength of the base and the acidity of the alcohol. Check all that apply. ► View Available Hint(s) CH3CH,OH + NH3 →CH,CH,O-NH CH3 CH3 H3C-C-H+NH3 → H3 C-C-H OH O-NH CH3CH2OH + NaNH, → CH3CH,O-Na* + NH3 CHC12 Cl₂…
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