hat quantity of joules of energy are needed to transform 11 kg of ice at 0.00°C to vapor at 155°C? Specific heat of water is cwater = 4186 J/kg C° Specific heat of steam is csteam = 2010 J/kg C° Latent heat of fusion of water is Lfusion = 3.33 X 105 J/kg Latent heat of vaporization of water is Lvaporization = 2.26 X 106 J/kg Boiling point of water = 100° C
hat quantity of joules of energy are needed to transform 11 kg of ice at 0.00°C to vapor at 155°C? Specific heat of water is cwater = 4186 J/kg C° Specific heat of steam is csteam = 2010 J/kg C° Latent heat of fusion of water is Lfusion = 3.33 X 105 J/kg Latent heat of vaporization of water is Lvaporization = 2.26 X 106 J/kg Boiling point of water = 100° C
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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What quantity of joules of energy are needed to transform 11 kg of ice at 0.00°C to vapor at 155°C?
Specific heat of water is cwater = 4186 J/kg C°
Specific heat of steam is csteam = 2010 J/kg C°
Latent heat of fusion of water is Lfusion = 3.33 X 105 J/kg
Latent heat of vaporization of water is Lvaporization = 2.26 X 106 J/kg
Boiling point of water = 100° C
Transcribed Image Text:Intensity level:
m
T = 2n,
k
B=10log
I.
Frequency:
f =
T
Intensity level difference:
Angular frequency:
k
w = 2n f
AB =10log
I,
m
PV = nRT, where R = 8.31 J/mole-K
Maximum Velocity, Acceleration:
A2n f
Ao = A(2nf}
Umax = A@ =
a max =
PV = constant,
PIV1 = P2V2
A = (27 f)
а max
Intensity:
Simple pendulum:
I= Pav
4ar?
T= 2n=
Doppler Shift:
Moving observer: f' = f(v+vo)/v
Speed sound temperature:
Moving source: f' = f(v)/ ( v-vs)
v= f2
Where vo = velocity of observer, vs is the
speed of the source, and v is the
speed of sound
T
U = (331m/s),
273K
Intensity of a wave:
power
Beat frequency fB
\f2- fil
I=
%3D
area
A
bol
Transcribed Image Text:Area of circle: A = Tr?
Rate of flow
Q = Av
t = F(sin0)r
T = Fl, wherel= lever arm
Bernoulli's equation:
1
P+
+ pgy, = P, +
1
pv,´ + pgy,
Equilibrium:
Te = T - 273.15°C
Στ=0
9
T =
-T. +32
5
Non-equilibrium:
5
Tc =-(T, - 32)
Στ= Ια
Тетреrature:
Moment of inertial for a point mass
revolving about a center at a distance r:
ΔL L,ΔΤ
AA = y A,AT Y = 2a
AV = BVAT B = 3a
I= Mr?
Kinetic Energy:
Specific Heat:
Translational: ½ mv²
Rotational: ½ Im?
(J/kg. 'C)
mAT
Q = mc(T, –T,)
Angular speed o =v/r
Qcold
=-Qhot
Tensile strain:
EQ = 0
Latent Heat:
F
AL
L.
Y -Young's modulus
phase change: Q=±mL
Energy Transfer:
ΔΤ
P =
At
Density:
Ar
M
p =
V
(kg/m²)
Thermal conductivity:
Pressure:
(T, – T.)
P = kA
L.
F
P=
A
(Ра)
Hooke's Law:
F =-kx
P = P, + pgh
Acceleration in simple harmonic
motion:
Archimedes' principle:
k
a =
B = P fuidV fa
m
fluid8
Elastic potential energy:
РЕ, %3D
-kx²
2
Equation of flow continuity:
Av, = A,v,
Period:
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