Specific heat (c)J/kg C900Problem 6: Consider a 0.775 kg aluminum pot containing 2.35 kg of water.SubstancesSolidsAluminumkcal/kg-C0.215Concrete8400.20Copper3870.0924Glass8400.20Human Body (37°C)35000.83Iron, steel4520.108LiquidsWater41861.000Mercury1390.0333Part (a) How much heat, in kilocalories, must be transferred to raise the temperature of the aluminum pot and the water from 30.0°C to the boilingpoint of water and then boil away 0.775 kg of water (L, = 539 kcal/kg)?Q =sin()cos()tan()78 9HOMEcotan()asin()acos()E6.atan()acotan()sinh()12.3cosh()tanh()cotanh()+ENDODegrees O RadiansVol BACKSPACE DEL CLEARFeedbackI give up!SubmitHintPart (b) How long, in seconds, does this take if the rate of heat transfer is 500 W?

Amount of het required depends upon specific heat constant and mass of matter to raise the…

Answered: Problem 6: Consider a 0.775 kg aluminum…

Similar questions

How much thermal energy/heat is required to raise 2.3 kg of lead from 300°C to 1800°C? Use Table 1 p281 and Table 1 p291 to help you. O 1.8 x 10°J O 2. 5 x 10°J O8.2 x 10³J O4.5 x 10°J x 10°J
You add 100.0 g of water at 50.1 °C to 100.0 g of ice at 0.00 °C. Some of the ice melts and cools the water to 0.00 °C. When the ice and water mixture reaches thermal equilibrium at 0 °C, how much ice has melted?
At a temperature of 22.00°C the hole in a steel plate has a diameter of 1.030 cm. If a steel rod with a diameter of 1.037 cm has to just slip through this hole, to what temperature should the plate be heated? The coefficient of area expansion of steel is 24 x 10-6/°C. °C
The volume of a gas at 20°C is 100cm3 at normal pressure. If it is heated to 100°C, its volume becomes 125cm3 at the same pressure, then volume coefficients of the gas (at normal pressure) is? a) 0.0033/°C b) 0.0025/°C c) 0.0030/°C d) 0.0021/°C
At what rate is heat lost through a 1.09 m × 3.16 m rectangular glass window that is 0.518 cm thick when the inside temperature is 20.1 °C and the outside temperature is 15.1 °C?The thermal conductivity of glass is 0.75 W/(m·°C) [1m = 100 cm]
A closed box is filled with dry ice at a temperature of -78.5 degreesC while the outside temperature is 21.0 degrees C the box is cubical measuring 0.4 m on a side and the thickness of the walls is 2.50 x 10^-2 m in one day 2.90 x 10^6 J of heat is conducted through the six walls find the thermal conductivity of the material from which the box is made
The temperature of a 5.00-kg lead brick is increased by 525 C°. If the specific heat capacity of lead is 128 J/(kg.C°), what is the increase in the mass of the lead brick when it has reached its final temperature? O 5.80 × 10- -11 kg O 9.12 × 10-11 kg O 1.60 × 10-12 kg O 3.73 × 10-12 kg O 2.80 × 10-12 kg
A student obtains the following data in a calorimetry experiment designed to measure the specific heat of aluminum. Initial temperature of water and calorimeter 70.3°C Mass of water 0.402 kg Mass of calorimeter 0.04 kg Specific heat of calorimeter 0.60 kJ/kg.°C Initial temperature of aluminum Mass of aluminum Final temperature of mixture (a) Use these data to determine the specific heat of aluminum. J/kg. °C (b) Is your result within 15% of 900 J/kg . °C? Yes No Need Help? 26.8°C 0.199 kg 66.4°C Read It
A person tries to cool down her bath water by adding 5.0 Kg of ice at 0°C to 75.0 Kg of water at 70°C. What is the final temperature of the water? (Lf = 333 KJ/Kg & cH2O =4186 J/Kg°C)
A bar of pure gold is heated to 105.0 °C. The specific heat capacity of gold is 1.29x10² J/1kg~°C). The gold is placed into 600.0 mL of ethyl alcohol initially at a temperature of 35.0 °C. The final temperature of the mixture is 37.0 °C. What is the mass of the gold?
Measurement of specific heat of metals Aluminum Cupper Mass of inner cup of calorimeter mcal, g 50 50 Specific heat of calorimeter Ccal, cal/(g °C) Specific heat of water Cw, cal/(g °C) 0.217 0.217 1.00 1.00 Mass of metal Mm, g 80 140 Mass of inner cup + water mcal + Mw, g 220 240 Mass of water Mw, g 170 190 Initial temperature of calorimeter and water to, °C Initial temperature of metal tm, °C 22 22 100 100 Final equilibrium temperature tr, °C 30 26 Thermal energy gain by calorimeter and water Qgain, cal Specific heat of metal Cm, cal/(g °C) Standard specific heat of metal Cst , cal/(g °C) 0.217 0.093 |% error Thermal energy lost = Thermal energy gained Thermal energy Q = cmAt %3D %3D Specific heat C |Thermal energy lost by metal = Thermal energy gained by (water + calorimeter) %3D EmMm(tm-tf)=(ccatMeat +CwMw)(tp- to) %3D (Ccaimcal+ Cymw)(tf- to). Gm = %3D Mm(tm - t;) |