A student obtains the following data in a calorimetry experiment designed to measure the specific heat of aluminum. Initial temperature of water and calorimeter 70.3°C Mass of water 0.402 kg Mass of calorimeter 0.04 kg 0.60 kJ/kg-°C Specific heat of calorimeter Initial temperature of aluminum Mass of aluminum Final temperature of mixture 26.8°C 0.199 kg 66.4°C (a) Use these data to determine the specific heat of aluminum. J/kg- °C (b) Is your result within 15% of 900 3/kg- °C? Yes No

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A student obtains the following data in a calorimetry experiment designed to measure the specific heat of aluminum.
Initial temperature of water and calorimeter 70.3°C
Mass of water
0.402 kg
Mass of calorimeter
0.04 kg
Specific heat of calorimeter
0.60 kJ/kg.°C
Initial temperature of aluminum
Mass of aluminum
Final temperature of mixture
(a) Use these data to determine the specific heat of aluminum.
J/kg. °C
(b) Is your result within 15% of 900 J/kg . °C?
Yes
No
Need Help?
26.8°C
0.199 kg
66.4°C
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Transcribed Image Text:A student obtains the following data in a calorimetry experiment designed to measure the specific heat of aluminum. Initial temperature of water and calorimeter 70.3°C Mass of water 0.402 kg Mass of calorimeter 0.04 kg Specific heat of calorimeter 0.60 kJ/kg.°C Initial temperature of aluminum Mass of aluminum Final temperature of mixture (a) Use these data to determine the specific heat of aluminum. J/kg. °C (b) Is your result within 15% of 900 J/kg . °C? Yes No Need Help? 26.8°C 0.199 kg 66.4°C Read It
Expert Solution
Introduction:

It is given that,

  • the mass of the calorimeter is, mc=0.04 kg,
  • the mass of the water is mw=0.402 kg,
  • the mass of the aluminum is, mAl=0.199 kg
  • the specific heat of the calorimeter is Ccl=0.60 kJ/kg·C
  • the specific heat of the water is Cw=4.187 kJ/kg·°C
  • the initial temperature of water and calorimeter is, T1=70.4°C
  • the initial temperature of the aluminum is TAi=26.8°C
  • the final temperature of the mixture is T=66.4°C

It is required to find the specific heat of aluminum, let the specific heat be CAl.

The amount of heat (J) absorbed by a substance per unit mass (Kg) as its temperature rises by 1 K is known as its specific heat capacity, or C.
The amount of heat Q needed to increase the temperature of a substance with mass m, and specific heat c from T1 to T2 is,

Q=mcT2-T1

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