halogens in organic compounds uses an argentometric titration. To 50 mL50 mL of anhydrous ether is added a carefully weighed sample (10−100 mg)(10−100 mg) of unknown, plus 2 mL2 mL of sodium dispersion and 1 mL1 mL of methanol. (Sodium dispersion is finely divided solid sodium suspended in oil. With methanol, it makes sodium methoxide, CH3O−Na+,CH3O−Na+, which attacks the organic compound, liberating halides.) Excess sodium is destroyed by slowly adding 2‑propanol, followed by 100 mL100 mL of water. (Sodium should not be treated directly with water because H2H2 can explode in the presence
halogens in organic compounds uses an argentometric titration. To 50 mL50 mL of anhydrous ether is added a carefully weighed sample (10−100 mg)(10−100 mg) of unknown, plus 2 mL2 mL of sodium dispersion and 1 mL1 mL of methanol. (Sodium dispersion is finely divided solid sodium suspended in oil. With methanol, it makes sodium methoxide, CH3O−Na+,CH3O−Na+, which attacks the organic compound, liberating halides.) Excess sodium is destroyed by slowly adding 2‑propanol, followed by 100 mL100 mL of water. (Sodium should not be treated directly with water because H2H2 can explode in the presence
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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A procedure7 for determining halogens in organic compounds uses an argentometric titration.
To 50 mL50 mL of anhydrous ether is added a carefully weighed sample (10−100 mg)(10−100 mg) of unknown, plus 2 mL2 mL of sodium dispersion and 1 mL1 mL of methanol. (Sodium dispersion is finely divided solid sodium suspended in oil. With methanol, it makes sodium methoxide, CH3O−Na+,CH3O−Na+, which attacks the organic compound, liberating halides.) Excess sodium is destroyed by slowly adding 2‑propanol, followed by 100 mL100 mL of water. (Sodium should not be treated directly with water because H2H2 can explode in the presence of O2O2: 2Na+2H2O⟶2NaOH+H2.)2Na+2H2O⟶2NaOH+H2.) This procedure gives a two‑phase mixture, with an ether layer floating on top of the aqueous layer that contains the halide salts. The aqueous layer is adjusted to pH 44 and titrated with Ag+,Ag+, using the electrodes in Figure 7‑5.How much 0.02916 M AgNO30.02916 M AgNO3 solution will be required to reach each equivalence point when 81.16 mg81.16 mg of 1‑bromo‑4‑chlorobutane (BrCH2CH2CH2CH2Cl;(BrCH2CH2CH2CH2Cl; FM 171.46)FM 171.46) are analyzed?
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