Consider the precipitation of anion X with metal cation M. IM + mX = M,X (s) K, = [M*FIX"" The following equation relates the volume of added M (Vu) to [M**] and [X] at a given point in the titration, and the initial volume of the X solution (V), plus the initial concentrations of M (C) and X" (C) x + m[M]- x[X 1 m- m[M]+ x[x ], Vu = V where [X] = (K/M"). Use a spreadsheet to generate a titration curve for 10.0 ml. of 0.100 M CrO titrated with 0.100 M Ag* to produce Ag, Cro, (s) (K, = 1.20 x 10 1). Report the volume of Ag* added at the following pAg* values of the titration. PAg* = 5.30 VA = ml. PAg* = 4.88 VA = ml PAg* = 4.10 Va = ml. ml pAg* = 2.80

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Consider the precipitation of anion X with metal cation M".
xM + mX = M, X(s)
Kp = [M** "'(X""
%3!
The following cquation relates the volume of added M" (V) to [M"*] and [X*] at a given point in the titration, and the initial
volume of the X" solution (K), plus the initial concentrations of M (C) and X (C)
xC + m[M"*1- x[X"1)
mC - m[M"]+ x[X")/
VM = V
where [X-) = (K/IM")").
Use a spreadsheet to generate a titration curve for 10.0 mL of 0.100 M CrO titrated with 0.100 M Ag* to produce Ag, Cro, (s)
(Kp = 1.20 x 10-12). Report the volume of Ag* added at the following pAg* values of the titration.
PAg* = 5.30
VA =
ml.
pAg* = 4.88
VA =
mL
%3!
PAg* = 4.10
ml.
pAg* = 2.80
V =
mL
ml.
pAg = 1.81
Va =
Transcribed Image Text:Consider the precipitation of anion X with metal cation M". xM + mX = M, X(s) Kp = [M** "'(X"" %3! The following cquation relates the volume of added M" (V) to [M"*] and [X*] at a given point in the titration, and the initial volume of the X" solution (K), plus the initial concentrations of M (C) and X (C) xC + m[M"*1- x[X"1) mC - m[M"]+ x[X")/ VM = V where [X-) = (K/IM")"). Use a spreadsheet to generate a titration curve for 10.0 mL of 0.100 M CrO titrated with 0.100 M Ag* to produce Ag, Cro, (s) (Kp = 1.20 x 10-12). Report the volume of Ag* added at the following pAg* values of the titration. PAg* = 5.30 VA = ml. pAg* = 4.88 VA = mL %3! PAg* = 4.10 ml. pAg* = 2.80 V = mL ml. pAg = 1.81 Va =
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