Standard solution : 0.201 grams of acetylsalicylic acid was combined with 10 mL of 0.5 M NaOH, then transfered to a 100 mL flask and filled the rest of the way with waterThen 0.500 mLs of the standard solution was transfered to a 10.00 mL flask and diluted to the 10 mL mark with 0.02 M of buffered iron chloride. Number of moles of NaOH = 0.005 molesSince the reaction between acetylsalicylic acid and NaOH is a 1:1 reaction, the number of moles of acetylsalicylic acid used in the reaction is also 0.005 moles.the concentration from analysis question 5: acetylsalicylic acid in the 100.00 mL volumetric flask is 0.050 M.From your plot, what is the value of εb? From the Beer- Lambert lawFor the aspirin sample, calculate the concentration of acetylsalicylic acid present using the value of εb that you found The concentration from analysis question 5 represents the concentration in the 10.00 mL sample that was prepared in the volumetric flask using an aliquot of the solution in the 100.00 mL volumetric flask. Calculate the concentration of acetylsalicylic acid in the 100.00 mL volumetric flask. Absorbance0.90.80.70.60.50.40.30.20.10Plot of Concentration vs Absorbancey = 350.5x + 0.075R² = 0.97320.00050.0010.0015Concentration (M)0.0020.0025 Mass of AcetylsalicylicAcidSolutionSolution #1Solution #2Solution #3Solution #4Solution #5Sample SolutionValue Unit0.201 gAbsorbance0.7700.6100.5230.4020.1730.745

Answered: Standard solution : 0.201 grams of…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Standard solution : 0.201 grams of acetylsalicylic acid was combined with 10 mL of 0.5 M NaOH, then transfered to a 100 mL flask and filled the rest of the way with water

Then 0.500 mLs of the standard solution was transfered to a 10.00 mL flask and diluted to the 10 mL mark with 0.02 M of buffered iron chloride.

Number of moles of NaOH = 0.005 moles

Since the reaction between acetylsalicylic acid and NaOH is a 1:1 reaction, the number of moles of acetylsalicylic acid used in the reaction is also 0.005 moles.

the concentration from analysis question 5: acetylsalicylic acid in the 100.00 mL volumetric flask is 0.050 M.

From your plot, what is the value of εb? From the Beer- Lambert law
For the aspirin sample, calculate the concentration of acetylsalicylic acid present using the value of εb that you found
The concentration from analysis question 5 represents the concentration in the 10.00 mL sample that was prepared in the volumetric flask using an aliquot of the solution in the 100.00 mL volumetric flask. Calculate the concentration of acetylsalicylic acid in the 100.00 mL volumetric flask.

Absorbance
0.9
0.8
0.7
0.6
0.5
0.4
0.3
0.2
0.1
0
Plot of Concentration vs Absorbance
y = 350.5x + 0.075
R² = 0.9732
0.0005
0.001
0.0015
Concentration (M)
0.002
0.0025

Mass of Acetylsalicylic
Acid
Solution
Solution #1
Solution #2
Solution #3
Solution #4
Solution #5
Sample Solution
Value Unit
0.201 g
Absorbance
0.770
0.610
0.523
0.402
0.173
0.745

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