H + {H He + n Q = 3.27 MeV {H + {H H + H = 4.03 MeV (43.35) H + H He + in Q = 17.59 MeV

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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Two nuclei having atomic numbers Z1 and Z2 approach each other with a total energy E. (a) When they are far apart, they interact only by electric repulsion. If they approach to a distance of 1.00 x 10-14 m, the nuclear force suddenly takes over to make them fuse. Find the minimum value of E, in terms of Z1 and Z2, required to produce fusion. (b) State how E depends on the atomic numbers. (c) If Z1 + Z2 is to have a certain target value such as 60, would it be energetically favorable to take Z1 = 1 and Z2 = 59, or Z1 = Z2 = 30, or some other choice? Explain your answer. (d) Evaluate from your expression the minimum energy for fusion for the D–D and D–T reactions (the first and third reactions in Eq. 43.35).

H + {H
He + n
Q = 3.27 MeV
{H + {H
H + H
= 4.03 MeV
(43.35)
H + H
He + in
Q = 17.59 MeV
Transcribed Image Text:H + {H He + n Q = 3.27 MeV {H + {H H + H = 4.03 MeV (43.35) H + H He + in Q = 17.59 MeV
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