H-0 CH,OH (b) NH, CH, H--0=C (b) 0-H-- (a) CH, CH, CH, CH H-C CH, CH, | (d) (CH.)4–NH, (a) CH, (d) CH, CH, CH,COOH (Б) H. [The image above is from a different textbook. Ask me later if you would like to know the reference.] The image above depicts protein tertiary structure. What type of tertiary structure is represented by the letter (d) in the image? hydrogen bonding 3 of these 4 responses are correct. disulfide linkage hydrophobic interaction salt bridge 0=J

H-0 CH,OH (b) NH, CH, H--0=C (b) 0-H-- (a) CH, CH, CH, CH H-C CH, CH, | (d) (CH.)4–NH, (a) CH, (d) CH, CH, CH,COOH (Б) H. [The image above is from a different textbook. Ask me later if you would like to know the reference.] The image above depicts protein tertiary structure. What type of tertiary structure is represented by the letter (d) in the image? hydrogen bonding 3 of these 4 responses are correct. disulfide linkage hydrophobic interaction salt bridge 0=J

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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ANALYTICAL CHEMISTRY MIDTERM ASSIGNMENT NO. 3 (BY GROUP) A. Identify the acid (acid1) on the left side and conjugate base (basel) on the right side. (a) HOCI + H,O=H,0* + OCI¯ (b) HONH, + H,0 HONH + OH (c) NH + H,0NH3 + H;O* (d) 2HCO, H,CO, + CO (e) PO + H,PO, 2HPO} B. Identify the base (base2) on the left side and conjugate acid ( acid2) on the right side. (a) HOCI + H,0=H,0* + OCI (b) HONH2 + H0 HONH + OH- (c) NH + H,0=NH, + H;O* (d) 2HCO, =H,CO, + CO (e) PO + H,PO, 2HPO} C. Calculations: 1. What is the concentration of hydronium ion in a 0.100 M solution of HCl? 2. What is the hydroxide concentration in the solution described in item 1? 3. What is the value of pH described in item 1? 4. Is the solution acidic or basic (refer to #3)? 5. Calculate the pH of water at 75 °C. Kw of water at 75 °C is 19.9 x 1014.
6. A nucleotide is the basic building block of nucleic acids. RNA and DNA are polymers made of long chains of nucleotides. A nucleotide consists of a sugar molecule (either ribose in RNA or deoxyribose in DNA) attached to a phosphate group and a nitrogen-containing base (the red nitrogen atom is connected to a sugar molecules). NH₂ adenine (A) HN. NH₂ NH (a) paired bases by hydrogen bonding. NH₂ HN HN cytosine (C) guanine (G) thymine (T) uracil (U) Which bases will make hydrogen-bonds together within an DNA? Draw structures of the (b) Which bases will make hydrogen-bonds together within an RNA? Draw structures of the paired bases by hydrogen bonding.
6. Predict the products of the following acid-base reactions, and predict whether the equilibrium lies to the left or to the right of the reaction arrow: (a) O2-(aq) + H2O(1)<---> (b) CH3COOH(aq) + HS-(aq)<---> (c) NO2-(aq) + H2O(1)<---> Group of answer choices A.) (a) 2 OH-; 100% to products (b) CH3COO- + H2S; towards products (c) HNO2 + OH-; towards reactants B.) (a) 2 OH-; 100% to products (b) CH3COO- + H2S; 100% to products (c) HNO2 + OH-; towards reactants C.) (a) 2 OH-; 100% to products (b) CH3COO- + H2S; towards products (c) HNO2 + OH-; towards products D.) (a) 2 OH-; towards reactants (b) CH3COO- + H2S; towards products (c) HNO2 + OH-; towards reactants
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QUESTION 6 Rank the following anions in order of increasing base strength. I. CH3CH₂ II. H₂C=CH |< | < ||| |||||| ||| < | < || III. HC=C:
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Write equations for the following acid-base reactions. Label the conjugate acids and bases, and show any inductive stabilization. Predict whether the equilibrium favors the reactants or products. Try to do this without using a table of pKa values, (a) CH3CH2OH + CH3NH- (b) F3CCOONa + Br3C¬COOH(c) CH3OH + H2SO4 (d) NaOH + H2S(e) CH3NH3+ + CH3O- (f) BrCH2CH2OH + F3C¬CH2O-(g) NaOCH2CH3 + Cl2CHCH2OH (h) H2Se + NaNH2(i) CH3CHFCOOH + FCH2CH2COO- (j) CF3CH2O- + FCH2CH2OH
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3.27 For each pair of structures below, identify the stronger acid, and explain your choice: H H N=H -N H H H (a) (c) H -" :0 H ΝΞΗ I H ΗΘΗ `N' H CONTA ΘΝ H (b) (d) H H H N H I H
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PQ-14. Given the equilibrium constants for these reactions: (8) H+ (3)'H³Ɔ (3)'H Ke% D2.8×10-21 Ke =9.5×10 13 CH, (g)+ H,O(g) =CH,OH(g)+ H, (g) What is the value of K. for this reaction? 2CH,OH(g) + H,(g)=C,H,(g)+ 2H,0(g) (B) 2.9x10-9 (C) 3.4x10% (D) 1.2x1029 (A) 9.5x10-13