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good working condition by satisfaction level. A numerical rating of 5 is assigned to very satisfied (VS), 4 to satisfied (S), 3 to neutral (N), 2 to somewhat dissatisfied (SD), and 1 to very dissatisfied (VD). Level of Satisfaction Movies Persons testing 50 of these units. He randomly selects the 12th to be the first unit to be tested. Which computer unit will be tested next? Watched 19-21 16-18 1 13-15 5 10-12 7 7-9 4-6 12 15 At least how many movies should one watch to belong to upper 5th percentile? 0-3 Number of Employces 25 VS (5) S(4) N (3) SD (2) VD (1) What is the employees' Level of Satisfaction with the company? And at what percent? 20 13 4 3 v can es and ems on ur

good working condition by satisfaction level. A numerical rating of 5 is assigned to very satisfied (VS), 4 to satisfied (S), 3 to neutral (N), 2 to somewhat dissatisfied (SD), and 1 to very dissatisfied (VD). Level of Satisfaction Movies Persons testing 50 of these units. He randomly selects the 12th to be the first unit to be tested. Which computer unit will be tested next? Watched 19-21 16-18 1 13-15 5 10-12 7 7-9 4-6 12 15 At least how many movies should one watch to belong to upper 5th percentile? 0-3 Number of Employces 25 VS (5) S(4) N (3) SD (2) VD (1) What is the employees' Level of Satisfaction with the company? And at what percent? 20 13 4 3 v can es and ems on ur

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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B. Read the given article/texts carefully. Then, complete the table and answer the questions that follow, Essential Question Text 1 Text 2 Text 3 The computer terminals in a school are labeled 1 to 300, The technician wants to know if the computers are in good working condition by testing 50 of these units. He randomly selects the 12th to be the first unit to be tested. Which computer unit will be tested next? Fifty people were surveyed The table shows the on the number of full-length frequency count of the employees' responses to the survey of employees' satisfaction level. A numerical rating of 5 is assigned to very satisfied (VS), 4 to satisfied (S), 3 to neutral (N), 2 to somewhat dissatisfied (SD), and 1 to very dissatisfied (VD). Number of Employces 25 movies watched in a year. Number of Movies Watched 19-21 16-18 13-15 Number of Регsons 1 5 7 10-12 7-9 8 4-6 0-3 At least how many movies should one watch to belong to upper 5th percentile? 12 15 Level of Satisfaction VS (5) S (4) N (3) SD (2) VD (1) What is the employees' Level of Satisfaction with the 20 13 4 3 How can issues and problems on company? And at what percent? Answer: your respective community be solved? Answer: Answer: Ore should watch at legst 1625 or 17 movies to beloe to The employees Level of Satisfaction with the company is The computer unit will be tested next is the 18th comouter the upper 5th percentile. 3,92 or aprox, (Satified) with 78,4% saifaction rate. unit. Supporting Texts: Supporting Texts: Supporting Texts: A person should wateh at least 17 movies to beleng to the Based on the aample groupad data of 65 amployeea, the The computer termnale in a achool are labeled 1 to 300. mean is 3.92 or approximately 4 which indioate as upper Sth percentile or the 95th percentile. This is beoause Sotiefied (S) on the level of sutiefaotion This les because I we used the formula Pr bpc +In*t/100 - of /fpe 1i The technician wanta to teet 50 urita and randomly sokecta eome up to my awn eomputotion and formula which la 12h to be the first unit to be tasted, The second or the where Ibpen first alass boundary in the loated cumulative weighted means VS(25) + K(20) + NC13) + SD14) + frequeney, n value we need to find, fa frequeney of the value (total number of persons), and ef= oumulative next computer unit will be tested is the 18th unit This is VD1) / total number of employees where VS= very because we use my buit up 2 formala which is umbere atiafind, S- autitafied, N- netral, SD- aomwhat of planned to test computer unita total computer termhale dissatisfied, VD= very dissatisfled. the mean is 392 or appreximately 4 which indicate as Saliefied (S) en the level of sutisfuction, ond total number of employeas 65, frequency of the class before the class with the value of n schools" and "first unit to be tested + anawer for the the given perentie. first formula". Reason: Reason: First, we get the the cumalative frequency and class Reason: To determine the level of satisfaction, we simply get the For this problem, we use my buit up 2 formulas and bourdariea ta oomplete the table, now we solve for the upper Sth percentile, Upper Sth percentile is 100-5-95th mean by getting the sum of multiplied frequency to ita' aubstitute the values needed, There are 300 oomputer percentile. So we reed to colesiate the 95th percentile. We numerical value and divided it by the total frequency form use the formula "Pr Ibpo +Entf/100 - ef fpa 11", We first find the n*1/100 95*5o cso is from the total number terminale in a school Fifty units are reeded to test if the the formula "weighted mean= VS(25) + S(20) + N(13) + computers are in good working condition. Since the first unit SD(4) + VD(1) / total number of employees". We of persons)a 4,750/100- 47.5. Then we loeate the to be tested is 12th, we need to divide firet the number of eumulotive frequeney value grester or equol to 47.5. After substitute the given vales to the formula, weighted mean dutermining, wa find the n=95, lbde-15.5, ef-47, fpe-2 eomputer terminals which is 300 to the numbers of units needed to test which is 50, It is equal to 6 as the interval of testing, ater that we use the first unit to be tested , 5(25) + 4(20) + 3(13) + 2(4) + 1(1) / 65 then we get the and i=18.5-15.5-3. We subetitute the vahes in the formula answer of 3.92 and if we round it off, we'l get the answer - of 4 that shows the employees' level of satiefoction of then inturprut, P95- 15.5 (47,5- 47 / 2)3, and the answer is 16.25. So vakue is 16.25 is in the upper 5th percentile or the 95th parcenntile round 16.25 up te the nearest whole number is 17 Tie io because we oon't have percent, we divided the mean to the highest value of level which is 12 to be added to the interval of testing and the Satisfind, And to determine the level of satiefaction in sum is 18 which will be the next computer unit to be tested decimcal valum tar number of movina axt is a diernin vartable). So we must have at least 17 movies to watch to of satisfaction and multiply it by 100 then we get the halang tn the pypar fith peronliln, anawer of 78,4% Common Ideas in Reasons: It is important to note that the observation are collected randomly, hence, there is no given biased/preference for one observation over another > It's worth noting that the observations are gathered at random, so there's no prejudice or biased for one observation over another. Enduring Understanding/Generalization: Frequery couts, grouped data, serve as pood starting of desriptive statistically analysis given a data set it gives more structured/ compact nalysis and it easinr /mure convenient to use as compared to ungrouped data > When oppused to ungroaped tlata, fruuency cuurta, BrOuperd data, served as a uselul beginning point for deseriptive statiratically analysis given a data het. It provideu a more structured/ condensed analysin and is uusier/more
Transcribed Image Text:B. Read the given article/texts carefully. Then, complete the table and answer the questions that follow, Essential Question Text 1 Text 2 Text 3 The computer terminals in a school are labeled 1 to 300, The technician wants to know if the computers are in good working condition by testing 50 of these units. He randomly selects the 12th to be the first unit to be tested. Which computer unit will be tested next? Fifty people were surveyed The table shows the on the number of full-length frequency count of the employees' responses to the survey of employees' satisfaction level. A numerical rating of 5 is assigned to very satisfied (VS), 4 to satisfied (S), 3 to neutral (N), 2 to somewhat dissatisfied (SD), and 1 to very dissatisfied (VD). Number of Employces 25 movies watched in a year. Number of Movies Watched 19-21 16-18 13-15 Number of Регsons 1 5 7 10-12 7-9 8 4-6 0-3 At least how many movies should one watch to belong to upper 5th percentile? 12 15 Level of Satisfaction VS (5) S (4) N (3) SD (2) VD (1) What is the employees' Level of Satisfaction with the 20 13 4 3 How can issues and problems on company? And at what percent? Answer: your respective community be solved? Answer: Answer: Ore should watch at legst 1625 or 17 movies to beloe to The employees Level of Satisfaction with the company is The computer unit will be tested next is the 18th comouter the upper 5th percentile. 3,92 or aprox, (Satified) with 78,4% saifaction rate. unit. Supporting Texts: Supporting Texts: Supporting Texts: A person should wateh at least 17 movies to beleng to the Based on the aample groupad data of 65 amployeea, the The computer termnale in a achool are labeled 1 to 300. mean is 3.92 or approximately 4 which indioate as upper Sth percentile or the 95th percentile. This is beoause Sotiefied (S) on the level of sutiefaotion This les because I we used the formula Pr bpc +In*t/100 - of /fpe 1i The technician wanta to teet 50 urita and randomly sokecta eome up to my awn eomputotion and formula which la 12h to be the first unit to be tasted, The second or the where Ibpen first alass boundary in the loated cumulative weighted means VS(25) + K(20) + NC13) + SD14) + frequeney, n value we need to find, fa frequeney of the value (total number of persons), and ef= oumulative next computer unit will be tested is the 18th unit This is VD1) / total number of employees where VS= very because we use my buit up 2 formala which is umbere atiafind, S- autitafied, N- netral, SD- aomwhat of planned to test computer unita total computer termhale dissatisfied, VD= very dissatisfled. the mean is 392 or appreximately 4 which indicate as Saliefied (S) en the level of sutisfuction, ond total number of employeas 65, frequency of the class before the class with the value of n schools" and "first unit to be tested + anawer for the the given perentie. first formula". Reason: Reason: First, we get the the cumalative frequency and class Reason: To determine the level of satisfaction, we simply get the For this problem, we use my buit up 2 formulas and bourdariea ta oomplete the table, now we solve for the upper Sth percentile, Upper Sth percentile is 100-5-95th mean by getting the sum of multiplied frequency to ita' aubstitute the values needed, There are 300 oomputer percentile. So we reed to colesiate the 95th percentile. We numerical value and divided it by the total frequency form use the formula "Pr Ibpo +Entf/100 - ef fpa 11", We first find the n*1/100 95*5o cso is from the total number terminale in a school Fifty units are reeded to test if the the formula "weighted mean= VS(25) + S(20) + N(13) + computers are in good working condition. Since the first unit SD(4) + VD(1) / total number of employees". We of persons)a 4,750/100- 47.5. Then we loeate the to be tested is 12th, we need to divide firet the number of eumulotive frequeney value grester or equol to 47.5. After substitute the given vales to the formula, weighted mean dutermining, wa find the n=95, lbde-15.5, ef-47, fpe-2 eomputer terminals which is 300 to the numbers of units needed to test which is 50, It is equal to 6 as the interval of testing, ater that we use the first unit to be tested , 5(25) + 4(20) + 3(13) + 2(4) + 1(1) / 65 then we get the and i=18.5-15.5-3. We subetitute the vahes in the formula answer of 3.92 and if we round it off, we'l get the answer - of 4 that shows the employees' level of satiefoction of then inturprut, P95- 15.5 (47,5- 47 / 2)3, and the answer is 16.25. So vakue is 16.25 is in the upper 5th percentile or the 95th parcenntile round 16.25 up te the nearest whole number is 17 Tie io because we oon't have percent, we divided the mean to the highest value of level which is 12 to be added to the interval of testing and the Satisfind, And to determine the level of satiefaction in sum is 18 which will be the next computer unit to be tested decimcal valum tar number of movina axt is a diernin vartable). So we must have at least 17 movies to watch to of satisfaction and multiply it by 100 then we get the halang tn the pypar fith peronliln, anawer of 78,4% Common Ideas in Reasons: It is important to note that the observation are collected randomly, hence, there is no given biased/preference for one observation over another > It's worth noting that the observations are gathered at random, so there's no prejudice or biased for one observation over another. Enduring Understanding/Generalization: Frequery couts, grouped data, serve as pood starting of desriptive statistically analysis given a data set it gives more structured/ compact nalysis and it easinr /mure convenient to use as compared to ungrouped data > When oppused to ungroaped tlata, fruuency cuurta, BrOuperd data, served as a uselul beginning point for deseriptive statiratically analysis given a data het. It provideu a more structured/ condensed analysin and is uusier/more
3. What concepts or properties do you need to solve the problems?
Transcribed Image Text:3. What concepts or properties do you need to solve the problems?
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