Childhood obesity: A national health survey weighed a sample of 532 boys aged 6-11 and found that 89 of them were overweight. They weighed a sample of469 girls aged 6-11 and found that 71 of them were overweight. Can you conclude that the proportion of boys who are overweight differs from the proportion ofgirls who are overweight? Let P₁ denote the proportion of boys who are overweight and let p₂ denote the proportion of girls who are overweight. Use thea = 0.10 level of significance and the critical value method with the table.(a) State the appropriate null and alternate hypotheses.(b) Compute the value of the test statistic.(c) State a conclusion at the a = 0.10 level of significance.Part 1 of 5(a) State the null and alternate hypotheses.Ho: P₁ = P₂H₁: P₁ P₂This hypothesis test is a two-tailed ▼test.Part: 1 / 5Part 2 of 5Find the critical value(s). Round the answer(s) to at least two decimal places. If there is more than one critical value, separate them with commas.Critical value(s):X

Answered: Image /qna-images/answer/24d9ecb8-6e0a-4015-89f8-d5fc1a1efff6.jpg

Answered: Childhood obesity: A national health…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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According to Pew Research Center surveys, 79% of U.S. adults were using the Internet in January 2011 and 83% were using it in January 2012 (USA TODAY, January 26, 2012). Suppose that these percentages are based on random samples of 1720 U.S. adults in January 2011 and 1970 in January 2012. a. Let p, and p, be the proportions of all U.S. adults who were using the Internet in January 2011 and January 2012, respectively. Construct a 95% confidence interval for p, - P2- Round your answers to three decimal places. to i
According to the Humane Society, 33% of households in the United States own at least one cat. You are interested in determining whether the proportion of households of the students at your school that own at least one cat is different from the national proportion. Suppose you survey an SRS of students at your school and find that 25% of them own cats, which yields a p-value of .092. Interpret this p-value.
A recent drug survey showed an increase in the use of drugs and alcohol among local high school seniors as compared to the national percent. Suppose that a survey of 100 local seniors and 100 national seniors is conducted to see if the proportion of drug and alcohol use is higher locally than nationally. Locally, 66 seniors reported using drugs or alcohol within the past month, while 62 national seniors reported using them. Conduct a hypothesis test at the 5% level. State the distribution to use for the test. What is the p-value?
In the American Heart Association journal Hypertension, researchers report that individuals who practice Transcendental Meditation (TM) lower their blood pressure significantly. If a random sample of 228 male TM practitioners meditate for 7.9 hours per week with a standard deviation of 2.25 hours, does that suggest that, on average, men who use TM meditate more than 7.5 hours per week? Quote a P-value in your conclusion. State the null and alternative hypotheses. Hot = 7.5 H₁: > 7.5 (Type integers or decimals. Do not round.) Find the test statistic. The test statistic is 2.68. (Round to two decimal places as needed.) Find the P-value. The P-value is 0.007 (Round to three decimal places as needed.) xample Textbook Clear all Final check
A sample of students involved in laboratory accidents was categorized by age. The results appear as: Find the median score
Sleep apnea is a condition in which the sufferers stop breathing momentarily while they are asleep. This condition results in lack of sleep and extreme fatigue during waking hours. A current estimate is that 11.911.9 million out of the 312.7312.7 million Americans suffer from sleep apnea, or approximately 3.8%3.8%. A safety commission is concerned about the percentage of commercial truck drivers who suffer from sleep apnea. They do not have any reason to believe that it would be higher or lower than the population’s percentage. To test the claim that the percentage of commercial truck drivers who suffer from sleep apnea is not 3.8%3.8%, a simple random sample of 347347 commercial truck drivers is examined by a medical expert, who concludes that 66 suffer from sleep apnea. Does this evidence support the claim that the percentage of commercial truck drivers who suffer from sleep apnea is not 3.8%3.8%? Use a 0.020.02 level of significance. Step 3 of 4 : Find the p-value. Round…
An article was published concerning the incidence of cardiac death attributable to earthquake in Los Angeles County on January 17, 1994. In the week before the earthquake there were an average of 15.6 cardiac deaths per day in Los Angeles County. On the day of the earthquake, there were 51 cardiac deaths. Among days with more than 10 admissions, what proportion fall on weekends?
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A restaurant chain would like to measure the proportion of customers who are generally satisfied with the service provided by its staff. At the end of the meal, as the check is delivered to the table, the server asks those at the table to rate their satisfaction with the service provided as "Very Satisfied," "Satisfied," or "Not Satisfied." During a one- week period, 147 customers were surveyed and 135 (93%) reported they were either Satisfied or Very Satisfied. How might the results be biased in obtaining an estimate of all customers who are satisfied with service? O Because of response bias, the survey results may overestimate the true proportion of satisfied customers. O Because of response bias, the survey results may underestimate the true proportion of satisfied customers. O Because of voluntary response bias, the survey results may overestimate the true proportion of satisfied customers. O Because customers were surveyed overa one-week period, the results should provide an…

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