Given the table of data below, what is the standard heat of reaction for the following process in klimo? Note that this reaction does not readily occur in the laboratory or in nature and the table provides more information than you actually need CH (9) H₂0 () CH₂O(g) + 2 H₂(g) Compound CH₂(g) H₂O(0) H₂O₂) 9106 HOOCHI CH,OH AH? (mol) -74.6 -285.8 -187.8 -115.9 -425.5 -2392

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**Standard Heat of Reaction Calculation**

Given the table of data below, what is the standard heat of reaction for the following process in kJ/mol? Note that this reaction does not readily occur in the laboratory or in nature and the table provides more information than you actually need.

\[ \text{CH}_4 (g) + \text{H}_2\text{O} (l) \rightarrow \text{CH}_2\text{O} (g) + 2 \text{H}_2 (g) \]

### Compound and Standard Enthalpy of Formation (ΔHf in kJ/mol)

| Compound | ΔHf (kJ/mol) |
|----------|--------------|
| CH4 (g)  | -74.8        |
| H2O (l)  | -285.8       |
| H2O (g)  | -187.8       |
| CH2O (g) | -115.9       |
| HCOOH (l) | -425.5      |
| CH3OH (l) | -239.2      |

### Options for Standard Heat of Reaction (ΔHr in kJ/mol)

- \( -115.9 \)
- \( -425.5 \)
- \( -220.7 \)
- \( -244.5 \)
- \( 220.7 \)

To calculate the standard heat of reaction (ΔHr), use the formula:

\[ \Delta H_r = \sum \Delta H_f(\text{products}) - \sum \Delta H_f(\text{reactants}) \]

*Substitute the values from the table into the equation to find the standard heat of the reaction.*

### Explanation of Table and Process

The table lists various compounds along with their standard enthalpy of formation (ΔHf in kJ/mol). When calculating the standard heat of reaction, it's essential to use the enthalpy values for products and reactants correctly.

- **Reactants:** 
  - \( \text{CH}_4 (g) \) with ΔHf = -74.8 kJ/mol
  - \( \text{H}_2\text{O} (l) \) with ΔHf = -285.8 kJ/mol

- **Products:** 
  - \( \text{CH}_2\text{O} (g) \) with ΔHf
Transcribed Image Text:**Standard Heat of Reaction Calculation** Given the table of data below, what is the standard heat of reaction for the following process in kJ/mol? Note that this reaction does not readily occur in the laboratory or in nature and the table provides more information than you actually need. \[ \text{CH}_4 (g) + \text{H}_2\text{O} (l) \rightarrow \text{CH}_2\text{O} (g) + 2 \text{H}_2 (g) \] ### Compound and Standard Enthalpy of Formation (ΔHf in kJ/mol) | Compound | ΔHf (kJ/mol) | |----------|--------------| | CH4 (g) | -74.8 | | H2O (l) | -285.8 | | H2O (g) | -187.8 | | CH2O (g) | -115.9 | | HCOOH (l) | -425.5 | | CH3OH (l) | -239.2 | ### Options for Standard Heat of Reaction (ΔHr in kJ/mol) - \( -115.9 \) - \( -425.5 \) - \( -220.7 \) - \( -244.5 \) - \( 220.7 \) To calculate the standard heat of reaction (ΔHr), use the formula: \[ \Delta H_r = \sum \Delta H_f(\text{products}) - \sum \Delta H_f(\text{reactants}) \] *Substitute the values from the table into the equation to find the standard heat of the reaction.* ### Explanation of Table and Process The table lists various compounds along with their standard enthalpy of formation (ΔHf in kJ/mol). When calculating the standard heat of reaction, it's essential to use the enthalpy values for products and reactants correctly. - **Reactants:** - \( \text{CH}_4 (g) \) with ΔHf = -74.8 kJ/mol - \( \text{H}_2\text{O} (l) \) with ΔHf = -285.8 kJ/mol - **Products:** - \( \text{CH}_2\text{O} (g) \) with ΔHf
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