Given the data: Volume of 1.00 M HCI (mL) 45.0 Volume of 1.00M NAOH (mL) 50.0 Initial Temperature ("C) 22.1 31.6 Final Temperature ("C) What is the enthalpy of neutralization or heat of reaction, AHN (in units of J/mol), assuming you calculated the heat of the reaction to be -3770 J.

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9) did i do this right?

**Given Data:**

- **Volume of 1.00 M HCl (mL):** 45.0
- **Volume of 1.00 M NaOH (mL):** 50.0
- **Initial Temperature (°C):** 22.1
- **Final Temperature (°C):** 31.6

**Problem:**

Calculate the enthalpy of neutralization or heat of reaction, ΔHₙ (in units of J/mol), assuming the heat of the reaction is -3770 J.

**Answer Box:**

8377 J/mol

This transcribed text includes a table with data relevant to a neutralization reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH). The given initial and final temperatures help determine the temperature change during the reaction. You are tasked with finding the enthalpy change of the reaction. The calculated answer provided is 8377 J/mol.
Transcribed Image Text:**Given Data:** - **Volume of 1.00 M HCl (mL):** 45.0 - **Volume of 1.00 M NaOH (mL):** 50.0 - **Initial Temperature (°C):** 22.1 - **Final Temperature (°C):** 31.6 **Problem:** Calculate the enthalpy of neutralization or heat of reaction, ΔHₙ (in units of J/mol), assuming the heat of the reaction is -3770 J. **Answer Box:** 8377 J/mol This transcribed text includes a table with data relevant to a neutralization reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH). The given initial and final temperatures help determine the temperature change during the reaction. You are tasked with finding the enthalpy change of the reaction. The calculated answer provided is 8377 J/mol.
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