9) did i do this right? **Given Data:**- **Volume of 1.00 M HCl (mL):** 45.0- **Volume of 1.00 M NaOH (mL):** 50.0- **Initial Temperature (°C):** 22.1- **Final Temperature (°C):** 31.6**Problem:**Calculate the enthalpy of neutralization or heat of reaction, ΔHₙ (in units of J/mol), assuming the heat of the reaction is -3770 J.**Answer Box:**8377 J/molThis transcribed text includes a table with data relevant to a neutralization reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH). The given initial and final temperatures help determine the temperature change during the reaction. You are tasked with finding the enthalpy change of the reaction. The calculated answer provided is 8377 J/mol.

Enthalpy of neutralization is the enthalpy change when 1 mol of water is formed from the reaction of…

Given the data: Volume of 1.00 M HCI (mL) 45.0 Volume of 1.00M NAOH (mL) 50.0 Initial Temperature ("C) 22.1 31.6 Final Temperature ("C) What is the enthalpy of neutralization or heat of reaction, AHN (in units of J/mol), assuming you calculated the heat of the reaction to be -3770 J.

Given the data: Volume of 1.00 M HCI (mL) 45.0 Volume of 1.00M NAOH (mL) 50.0 Initial Temperature ("C) 22.1 31.6 Final Temperature ("C) What is the enthalpy of neutralization or heat of reaction, AHN (in units of J/mol), assuming you calculated the heat of the reaction to be -3770 J.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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