Given the SPSS output (a)Are the samples independent? Justify your answer. (b)State the appropriate null and alternative hypotheses to test whether the medication has been effective in decreasing blood glucose level.  c) Calculate the value of the test statistic and test the hypotheses assuming α = 0.05 using critical value-approach.  d) Find the p-value. NOTE: Hypotheses should be written using notation μD and indicate how you obtain the difference D = Before Medication - After Medication or D = After Medication - Before Medication which my alter your hypotheses.  Although SPSS provides p-value (i.e. Sig-(2-tailed) in SPSS output) assuming the test is two-tailed, students need to divide the SPSS p-value by 2 to get the right p-value for our right-tailed test. This problem also needs to be solved using critical value approach. You need to find the critical value from the t-table as critical value is usually not reported in SPSS output and carry out all 4-step process to do the hypothesis test.

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Given the SPSS output

(a)Are the samples independent? Justify your answer.

(b)State the appropriate null and alternative hypotheses to test whether the medication has been effective in decreasing blood glucose level. 

c) Calculate the value of the test statistic and test the hypotheses assuming α = 0.05 using critical value-approach. 

d) Find the p-value.

NOTE:

Hypotheses should be written using notation μD and indicate how you obtain the difference D = Before Medication - After Medication or D = After Medication - Before Medication which my alter your hypotheses. 

Although SPSS provides p-value (i.e. Sig-(2-tailed) in SPSS output) assuming the test is two-tailed, students need to divide the SPSS p-value by 2 to get the right p-value for our right-tailed test. This problem also needs to be solved using critical value approach. You need to find the critical value from the t-table as critical value is usually not reported in SPSS output and carry out all 4-step process to do the hypothesis test.

 

T-Test
[DataSet2]
Paired Samples Statistics
Std. Error
Mean
Std. Deviation
Mean
Pair 1
BEFORE_MED
11.4000
10
1.02956
.32558
AFTER_MED
9.0600
10
1.44160
.45588
Paired Samples Correlations
Correlation
Sig.
BEFORE_MED &
AFTER_MED
Pair 1
10
.697
.025
Paired Samples Test
Paired Differences
95% Confidence Interval of the
ferenc
Std. Error
Mean
Std. Deviation
Mean
Lower
Upper
df
Sig. (2-tailed)
BEFORE_MED-
AFTER_MED
Pair 1
2.34000
1.03409
.32701
1.60026
3.07974
7.156
9
.000
Transcribed Image Text:T-Test [DataSet2] Paired Samples Statistics Std. Error Mean Std. Deviation Mean Pair 1 BEFORE_MED 11.4000 10 1.02956 .32558 AFTER_MED 9.0600 10 1.44160 .45588 Paired Samples Correlations Correlation Sig. BEFORE_MED & AFTER_MED Pair 1 10 .697 .025 Paired Samples Test Paired Differences 95% Confidence Interval of the ferenc Std. Error Mean Std. Deviation Mean Lower Upper df Sig. (2-tailed) BEFORE_MED- AFTER_MED Pair 1 2.34000 1.03409 .32701 1.60026 3.07974 7.156 9 .000
Paired Samples Effect Sizes
95% Confidence Interval
Point
Standardizer
Estimate
Lower
Upper
BEFORE_MED -
AFTER_MED
Pair 1
Cohen's d
1.03409
2.263
1.048
3.447
Hedges' correction
1.07982
2.167
1.003
3.301
a. The denominator used in estimating the effect sizes.
Cohen's d uses the sample standard deviation of the mean difference.
Hedges' correction uses the sample standard deviation of the mean difference, plus a correction factor.
Transcribed Image Text:Paired Samples Effect Sizes 95% Confidence Interval Point Standardizer Estimate Lower Upper BEFORE_MED - AFTER_MED Pair 1 Cohen's d 1.03409 2.263 1.048 3.447 Hedges' correction 1.07982 2.167 1.003 3.301 a. The denominator used in estimating the effect sizes. Cohen's d uses the sample standard deviation of the mean difference. Hedges' correction uses the sample standard deviation of the mean difference, plus a correction factor.
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