Match the p-values with the appropriate conclusion:1. 0.00010 II. 0.0508 III. 0.0338 IV. 0.1509(a) The evidence against the null hypothesis is significant, but only at the 10% level.(b) The evidence against the null and in favor of the alternative is very strong.(c) There is not enough evidence to reject the null hypothesis, even at the 10% level.(d) The result is significant at a 5 % level but not at a 1 % level.

Certain statements regarding p-value and significance level are given. It is required to match the…

Answered: Match the p-values with the appropriate…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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18% of all college students volunteer their time. Is the percentage of college students who are volunteers smaller for students receiving financial aid? Of the 379 randomly selected students who receive financial aid, 57 of them volunteered their time. What can be concluded at the a = 0.01 level of significance? a. For this study, we should use z-test for a population proportion b. The null and altemative hypotheses would be: Họ: P (please enter a decimal) Hi: P (Please enter a decimal) c. The test statistic zv (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is > v f. Based on this, we should fail to reject g. Thus, the final conclusion is that ... a the null hypothesis. O The data suggest the population proportion is not significantly lower than 18% at a = 0.01, so there is sufficient evidence to conclude that the percentage of financial aid recipients who volunteer is equal to 18%. O The data suggest the…
State whether the standardized test statistic z indicates that you should reject the null hypothesis. (a) z= 1.225 (b) z = - 1.329 (c) z = - 1.517 (d) z = - 1.158 2 =-1285 (a) For z= 1.225, should you reject or fail to reject the null hypothesis? O A. Fail to reject H, because z - 1.285. O C. Fail to reject H, because z> - 1.285. O D. Reject H, because z<- 1.285.
A medical researcher wants to determine if the average hospital stay of patients that undergo a certain procedure is less than 6 days. The hypotheses for this scenario are as follows: Null Hypothesis: μ ≥ 6, Alternative Hypothesis: μ < 6. If the researcher takes a random sample of patients and calculates a p-value of 0.4381 based on the data, what is the appropriate conclusion? Conclude at the 5% level of significance.Question 12 options: 1) We did not find enough evidence to say the true average hospital stay of patients is longer than 6 days. 2) We did not find enough evidence to say the true average hospital stay of patients is shorter than 6 days. 3) The true average hospital stay of patients is significantly shorter than 6 days. 4) The true average hospital stay of patients is longer than or equal to 6 days. 5) We did not find enough evidence to say a significant difference exists
(c) Find the standardized test statistic, z.(Round to two decimal places as needed.) (d) Decide whether to reject or fail to reject the null hypothesis. (e) Interpret the decision in the context of the original claim.
(a) State the alternative hypothesis.(b) State the type of the test required and its rejection area at 0.05 significance level.(c) Calculate the test statistic, Z for the population proportion.
You are more likely to make a type 1 error with a sample of n=4 than with a sample of n=100 if you use α= .05 for both tests. A. True B. False
Women athletes at a certain university have a long-term graduation rate of 67%. Over the past several years, a random sample of 38 women athletes at the school showed that 23 eventually graduated. Does this indicate that the population proportion of women athletes who graduate from the university is now less than 67%? Use a 10% level of significance. What is the level of significance? (b) State the null and alternate hypotheses. H0: p = 0.67; H1: p > 0.67 H0: p = 0.67; H1: p ≠ 0.67 H0: p < 0.67; H1: p = 0.67 H0: p = 0.67; H1: p < 0.67 What sampling distribution will you use? The Student's t, since np < 5 and nq < 5. The standard normal, since np < 5 and nq < 5. The standard normal, since np > 5 and nq > 5. The Student's t, since np > 5 and nq > 5. What is the value of the sample test statistic? (Round your answer to two decimal places.) Find the P-value of the test statistic. (Round your answer to four decimal places.)…
20% of all college students volunteer their time. Is the percentage of college students who are volunteers smaller for students receiving financial aid? Of the 326 randomly selected students who receive financial aid, 46 of them volunteered their time. What can be concluded at the αα = 0.05 level of significance? Z- test for a population proportion The null and alternative hypotheses would be: H0:H0: p = __?__ (please enter a decimal) H1:H1: p is ( choose one <, = or not equal) ____?___ncorr __?__(Please enter a decimal) The test statistic z= __?__(please show your answer to 3 decimal places.) The p-value = __?__(Please show your answer to 4 decimal places.) Thus, the final conclusion is that ... a. The data suggest the population proportion is not significantly lower than 20% at αα = 0.05, so there is insufficient evidence to conclude that the percentage of financial aid recipients who volunteer is lower than 20%. b. The data…
A sample has a mean of M = 39.50, a standard deviation of s = 4.30, and produces a t statistic of t = +2.14. For a two-tailed hypothesis test, which of the following is the correct statistical decision for this sample? A. The researcher should reject the null hypothesis with α = .05 but not with α = .01. B. The researcher should reject the null hypothesis with either α = .05 or α = .01. C. The researcher should reject the null hypothesis with α = .01 but not with α = .05. D. This is impossible to determine based on the provided information.
You may need to use the appropriate technology to answer this question. The following data are from a completely randomized design. In the following calculations, use a = 0.05. Treatment Treatment Treatment 3 64 82 69 47 71 53 54 87 60 35 64 46 50 76 57 148.67 108.67 96.67 (a) Use analysis of variance to test for a significant difference among the means of the three treatments.
Only 16% of registered voters voted in the last election. Will voter participation increase for the upcoming election? Of the 327 randomly selected registered voters surveyed, 56 of them will vote in the upcoming election. What can be concluded at the αα = 0.05 level of significance? For this study, we should use: z-test for a population proportion or t-test for a population mean The null and alternative hypotheses would be: H0:H0: ? μ p Select an answer ≠ < = > (please enter a decimal) H1:H1: ? p μ Select an answer > = ≠ < (Please enter a decimal) The test statistic ? z or t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? > ≤ αα Based on this, we should Select an answer: accept, reject or fail to reject the null hypothesis. Thus, the final conclusion is that ... The data suggest the population proportion is not significantly higher than 16% at αα = 0.05, so there…
16% of all college students volunteer their time. Is the percentage of college students who are volunteers smaller for students receiving financial aid? Of the 313 randomly selected students who receive financial aid, 31 of them volunteered their time. What can be concluded at the αα = 0.10 level of significance? For this study, we should use Select an answer z-test for a population proportion t-test for a population mean The null and alternative hypotheses would be: H0:H0: ? p μ Select an answer < ≠ = > (please enter a decimal) H1:H1: ? μ p Select an answer > ≠ = < (Please enter a decimal) The test statistic ? t z = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? > ≤ αα Based on this, we should Select an answer reject accept fail to reject the null hypothesis. Thus, the final conclusion is that ... The data suggest the population proportion is not significantly lower…

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