Part II: Hypotheses: Calories of the same students will be significantly different based on theterm typeQ1. What test did you use to assess hypothesis?Q2. What are the 2 assumptions that should be tested on SPSS? Can we make theseassumptions based on the given data? No need to provide figuresQ3. Is the above hypothesis true? Explain by providing the P valueQ4. Is there a need for post-hoc tests here? Why or why not. If yes, copy, paste and interpret theresult from the post-hoc test to this Word doc. If "No", do not copy anything at allFall Term245344451251145352547552452251446542142143Spring Term141145239141546337548445148337444141530435Summer Term233133320528435223348430297439386438272397

Fall termSpring termSummer term2451412333441451334512393202511415281455464353523372235475483485524454304521482972513374394464443865421414381425302721434353971)The appropriate statistical test to assess whether the calories of the same students significantly differ based on the term type is an Analysis of Variance (ANOVA) test.ANOVA evaluates whether there are statistically significant differences in means across multiple groups.2)Two important assumptions to be checked for ANOVA are:Homogeneity of variances: It assumes that the variance of the dependent variable is equal across different groups.Normality of residuals: It assumes that the residuals are normally distributed.Steps for performing the Homogeneity of Variances test using SPSS is given below:Step 1) Run the Levene's test for homogeneity of variances on the residuals.Step 2) Go to Analyze > Compare Means > One-Way ANOVA.Step 3) Move the residuals into the "Dependent List" box and the grouping variable (term type) into the "Factor" box.Step 4) Click on "Options."Step 5) Check "Homogeneity of variance test."Step 6) Choose "Levene" from the dropdown menu.Step 7) Click "Continue" and then "OK."Output:The P-value = 0.1051Since the P-value (0.1051) is greater than the significance level (0.05), we failed to reject the null hypothesis. Conclusion:-Failed to reject H0, There is not sufficient evidence for significant differences between three variances. Hence assumption for the homogeneity of variances is satisfied.3) Fall termSpring termSummer term245141233344145133451239320251141528145546435352337223547548348552445430452148297251337439446444386542141438142530272143435397Sum486345774879Mean347.3571429326.9285714348.5Count141414305005.2143354184.9286151151.5Source of VariationSSdfMSFP-valueBetween Groups4125.1428622062.5710.0992670.905729Within Groups810341.6433920777.99Total814466.78641Null hypothesis: H0:μ1=μ2=μ3 Alternative hypothesis: HA : At-least one of the μ is not equal.For this analysis, the significance level is 0.05.F statistics is given by:- F = 0.0993Use the excel formula, "=F.DIST.RT(0.0993,2,39)" to determine the P-value: The P-value = 0.9057Since the P-value (0.9057) is greater than the significance level (0.05), we failed to reject the null hypothesis. Conclusion:-Failed to reject H0, There is not sufficient evidence for significant differences between the calories of the same students based on their term type.4) If the ANOVA test indicates significant differences among terms, then post-hoc tests can be performed to determine which specific groups differ from each other.For the given scenario, Anova test results are not statistically significant and there is no significant difference between the calories of the same students based on their term type. Therefore, conducting post-hoc tests might not be appropriate for the scenario.1)The appropriate statistical test to assess whether the calories of the same students significantly differ based on the term type is an Analysis of Variance (ANOVA) test.ANOVA evaluates whether there are statistically significant differences in means across multiple groups.2)Two important assumptions to be checked for ANOVA are:Homogeneity of variances: It assumes that the variance of the dependent variable is equal across different groups.Normality of residuals: It assumes that the residuals are normally distributed.Steps for performing the Homogeneity of Variances test using SPSS is given below:Step 1) Run the Levene's test for homogeneity of variances on the residuals.Step 2) Go to Analyze > Compare Means > One-Way ANOVA.Step 3) Move the residuals into the "Dependent List" box and the grouping variable (term type) into the "Factor" box.Step 4) Click on "Options."Step 5) Check "Homogeneity of variance test."Step 6) Choose "Levene" from the dropdown menu.Step 7) Click "Continue" and then "OK."Output:The P-value = 0.1051Since the P-value (0.1051) is greater than the significance level (0.05), we failed to reject the null hypothesis. Conclusion:-Failed to reject H0, There is not sufficient evidence for significant differences between three variances. Hence assumption for the homogeneity of variances is satisfied.3) Null hypothesis: H0:μ1=μ2=μ3 Alternative hypothesis: HA : At-least one of the μ is not equal.For this analysis, the significance level is 0.05.F statistics is given by:- F = 0.0993Use the excel formula, "=F.DIST.RT(0.0993,2,39)" to determine the P-value: The P-value = 0.9057Since the P-value (0.9057) is greater than the significance level (0.05), we failed to reject the null hypothesis. Conclusion:-Failed to reject H0, There is not sufficient evidence for significant differences between the calories of the same students based on their term type.4) If the ANOVA test indicates significant differences among terms, then post-hoc tests can be performed to determine which specific groups differ from each other.For the given scenario, Anova test results are not statistically significant and there is no significant difference between the calories of the same students based on their term type. Therefore, conducting post-hoc tests might not be appropriate for the scenario.