### Thermodynamic Calculations for Chemical ReactionsGiven the information:For the reaction:\[ A + B \rightarrow 2D \]\[\Delta H^\circ = -646.9 \, \text{kJ} \qquad \Delta S^\circ = 294.0 \, \text{J/K}\]For the reaction:\[ C \rightarrow D \]\[\Delta H^\circ = 390.0 \, \text{kJ} \qquad \Delta S^\circ = -179.0 \, \text{J/K}\]Calculate \(\Delta G^\circ\) at 298 K for the reaction:\[ A + B \rightarrow 2C \]### CalculationThe Gibbs free energy change \(\Delta G^\circ\) for a reaction at temperature \(T\) is given by the equation:\[\Delta G^\circ = \Delta H^\circ - T\Delta S^\circ\]Where:- \(\Delta H^\circ\) is the standard enthalpy change.- \(\Delta S^\circ\) is the standard entropy change.- \(T\) is the temperature in Kelvin.**Put the given values into the formula to calculate \(\Delta G^\circ\) for the given reaction.**\[\Delta G^\circ = \]

Answered: Image /qna-images/answer/4c509179-ae02-45d5-8c3e-df217fe06e3c.jpg

Answered: Given the information A + B – 2D ΔΗ…

Given the information A + B – 2D ΔΗ -646.9 kJ AS 294.0 J/K C– D AH° = 390.0 kJ AS -179.0 J/K %3D calculate AG° at 298 K for the reaction A + B 2C AG° =

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

Ka = 4.5 × 10-4 at 25°C of nitrous acid (HNO2). What is the ΔG value at equilibrium?
Use data to compute AG° at 82.0°C for the following reaction. 4FECI3(s) + 302(g) → 2FE203(s) + 6CI2(3) AH°t (FeCl3(s)) = -399.5 kJ mol-1 AH°t (Fe2O3(s) = -824.2 kJ mol-1 AS° (FeCl3(s)) = 142.3 J mol 1 K-1 AS° (Fe2O3(s)) = 87.4 J mol-1 K-1 AS° (Cl2(g)) = 223.1 J mol-1 K-1 AS° (O2(g)) = 205.152 J mol-1 K1 AG° = i kJ eTextbook and Media Save for Later Attempts: 0 of 3 used Submit Answer
Calculate the AG°xn at 298 K for the following reaction. 2 HNO3(aq) + NO(g) → 3 NO2(g) + H2O(I) AG°† (kJ/mol) -110.9 87.6 51.3 -237.1 O +51,0 kJ O -162.5 kJ O -87.6 kJ O -51.0 kJ O +162.5 kJ
The following reaction has a AG° value of +8.43 kJ/mol at 25 °C. HA(aq) + H20(1) =H;O*(aq) + A (aq) Calculate the KA for the acid HA.
(H2 ) →(12 ) +( 2HI) (AS = 82.4 J/K ),(AH = 25.9 KJ/K ) %3D %3D Calculate AG for this reaction at 25 C°
What is AG° for the reaction CH;OH(g) → CO(g) + 2 H2(g) at 25°C? AH° = +90.7 kJ/mol AS° = +221 J/mol•K kJ/mol 1 2 3 4 C 7 8 9. +/- x 10 0 LO
Calcualte the change in Gibbs free energy (AG°) for the reaction below given the change in enthalpy (AH°) is CO (g) + H,O (g) – CO2 (g) + H2 (B) DH° = -41.2 kJ and Ds° = -135 J/mol K at 298 K -0.97 kļ/mol a 40188.8 kļ/mol -81.43 kJ/mol -0.77 kļ/mol
Determine the AG° for the reaction of hydrogen and oxygen to form water. 2H2 (g) + O2 (g)→ 2H2O (g) AS°= -89.0 J/K AH°= -483.6 KJ
Use the following information to calculate the standard free energy change (AG°) and equilibrium constant (K) for the following system: CaCO3(s) = CaO(s) + CO2(g) T= 900.0 °C AH;° values (kJ/mol): CaO(s) = -634.9, CO2(g) = -393.51, CaCO3(s) =–1220.0 %3D S° values (J/mol K): CaO(s) = 110.0, CO2(g) = 213.8, CACO3(s) = 38.1 %3D %3D %3D
Calculate the AH°, AS°, and AG° at 298 K for the following reaction: (Use the values found in Thermodynamic Properties to calculate your answers for questions a and b.) Al2O3(s) + 3 C(graphite) + 3 Cl₂(g) → 2 AICI 3(s) + 3 CO(g) 4.0 -64 a) ΔΗΟ kJ/mol b) AS° ✓ J/K.mol kJ/mol (Determine from the temperature, AH and AS) c) AGO 4.0 76.9 4.0 -89 (d) Is the reaction extensive at standard conditions and 298 K? O Yes O NO (e) Write the expression for K. (Format example: Kp = pHC12 / pH₂. pCl₂ would be entered as K_{p} = pHCI^{2}/pH_{2}. pCl_{2}.) Help chemPad XX (PCO)3 (pCl₂)³ ← Greek (PCO)^3/(pCl_2)^3 Your answer provides a different type of equation than was expected. (f) Calculate the value of K at 298 K 2.51e-16 X (Please answer to 3 significant figures.) (g) Estimate the value of K at 600 K. 1.79e-8 X (Please answer to 3 significant figures.)
What is AG° for the reaction CH₂OH(g) → CO(g) + 2 H₂(g) at 25°C? AH° = +90.7 kJ/mol kJ/mol
R = 8.314 mol-K F = 96,485 mol AG = AG° + RT · In(Q) ΔΕ - (E) · In(Q) ΔΕ. Half Reaction (Note: All given as reduction) E° (V) 02 (g) + 4 H*(aq) + 4 e 2 H20 (1) 1.229 Z2 (s) + 2 e 3+ (aq) + 3 e 2z (aq) 0.426 A (s) 0.292 2 H20 (1) + 2 e G2+ (aq) + 2 e M²+ (aq) + 2 e¯ H2 (g) + 2 OH¯ (aq) - 0.828 G (s) - 1.245 M (s) - 1.893 A student constructs a voltaic electrochemical cell with two metal electrodes [metal G and metal A] in their respective aqueous nitrate solutions [G(NO3)2 and A(NO3)3]. Use this information, as well as the reduction potentials in the table above to complete each statement below. Consider the same cell from the above prompt. Calculate A E°. cell for this galvanic cell given the reference information given at the top of the quiz. Report your answer with 3 decimal places. You do not need to report units with your answer.