Given the information A + B – 2D ΔΗ -646.9 kJ AS 294.0 J/K C– D AH° = 390.0 kJ AS -179.0 J/K %3D calculate AG° at 298 K for the reaction A + B 2C AG° =

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### Thermodynamic Calculations for Chemical Reactions

Given the information:

For the reaction:
\[ A + B \rightarrow 2D \]
\[
\Delta H^\circ = -646.9 \, \text{kJ} \qquad \Delta S^\circ = 294.0 \, \text{J/K}
\]

For the reaction:
\[ C \rightarrow D \]
\[
\Delta H^\circ = 390.0 \, \text{kJ} \qquad \Delta S^\circ = -179.0 \, \text{J/K}
\]

Calculate \(\Delta G^\circ\) at 298 K for the reaction:
\[ A + B \rightarrow 2C \]

### Calculation

The Gibbs free energy change \(\Delta G^\circ\) for a reaction at temperature \(T\) is given by the equation:
\[
\Delta G^\circ = \Delta H^\circ - T\Delta S^\circ
\]

Where:
- \(\Delta H^\circ\) is the standard enthalpy change.
- \(\Delta S^\circ\) is the standard entropy change.
- \(T\) is the temperature in Kelvin.

**Put the given values into the formula to calculate \(\Delta G^\circ\) for the given reaction.**

\[
\Delta G^\circ = 
\]
Transcribed Image Text:### Thermodynamic Calculations for Chemical Reactions Given the information: For the reaction: \[ A + B \rightarrow 2D \] \[ \Delta H^\circ = -646.9 \, \text{kJ} \qquad \Delta S^\circ = 294.0 \, \text{J/K} \] For the reaction: \[ C \rightarrow D \] \[ \Delta H^\circ = 390.0 \, \text{kJ} \qquad \Delta S^\circ = -179.0 \, \text{J/K} \] Calculate \(\Delta G^\circ\) at 298 K for the reaction: \[ A + B \rightarrow 2C \] ### Calculation The Gibbs free energy change \(\Delta G^\circ\) for a reaction at temperature \(T\) is given by the equation: \[ \Delta G^\circ = \Delta H^\circ - T\Delta S^\circ \] Where: - \(\Delta H^\circ\) is the standard enthalpy change. - \(\Delta S^\circ\) is the standard entropy change. - \(T\) is the temperature in Kelvin. **Put the given values into the formula to calculate \(\Delta G^\circ\) for the given reaction.** \[ \Delta G^\circ = \]
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