R = 8.314 mol-KF = 96,485 molAG = AG° + RT · In(Q)ΔΕ -(E) · In(Q)ΔΕ.Half Reaction (Note: All given as reduction)E° (V)02 (g) + 4 H*(aq) + 4 e2 H20 (1)1.229Z2 (s) + 2 e3+(aq) + 3 e2z (aq)0.426A (s)0.2922 H20 (1) + 2 eG2+ (aq) + 2 eM²+ (aq) + 2 e¯H2 (g) + 2 OH¯ (aq)- 0.828G (s)- 1.245M (s)- 1.893A student constructs a voltaic electrochemical cell with two metal electrodes[metal G and metal A] in their respective aqueous nitrate solutions[G(NO3)2 and A(NO3)3].Use this information, as well as the reduction potentials in the table above tocomplete each statement below.Consider the same cell from the above prompt.Calculate A E°.cellfor this galvanic cell given the reference information given at the topof the quiz.Report your answer with 3 decimal places. You do not need to report units with youranswer.

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Answered: Calculate AE° cell

Science

Chemistry

Calculate AE° cell

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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