A tub of water containing Cu²⁺(aq) is subjected to a current of 0.3 amperes for 30 minutes. How many grams of Cu(s) can be produced. A) 0.18g B) 0.354g C) 1.52g D) 2.13g
A tub of water containing Cu²⁺(aq) is subjected to a current of 0.3 amperes for 30 minutes. How many grams of Cu(s) can be produced. A) 0.18g B) 0.354g C) 1.52g D) 2.13g
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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A tub of water containing Cu²⁺(aq) is subjected to a current of 0.3 amperes for 30 minutes. How many grams of Cu(s) can be produced.
A) 0.18g
B) 0.354g
C) 1.52g
D) 2.13g
Expert Solution
Introduction:
Faraday's law of electrolysis states that the mass of metal produced or deposited at electrode is directly proportional to the charge. Charge is calculated by multiplying current with time. Molar mass and Faraday's constant have fixed value. The formula for calculating the mass of metal is as follows;
Where;
w = mass of metal in grams
I = current in amperes
t = time in seconds
M = molar mass of metal in g/mol
Z = number of electrons (charge on metal ion)
F = Faraday's constant (96500 C/mol)
Given data:
I = 0.3 A
M = 63.546 g/mol
Z = 2
F = 96500 C/mol
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