Given the following reactions: Anode: NO3- + 2H+ + e- --> NO2 + H2O Cathode: 2H+ + 2e- --> H2 Redox: 2NO2(g) + 2 H2O (l) --> 2NO3-(aq) + 2H+(aq) + H2(g) Conditions: [0.15 atm] [0.18 atm] [0.1 M] [0.1 M] [0.67 atm] Find the cell potential, E Report your answer in 2 decimal places. Do not include the unit
Given the following reactions: Anode: NO3- + 2H+ + e- --> NO2 + H2O Cathode: 2H+ + 2e- --> H2 Redox: 2NO2(g) + 2 H2O (l) --> 2NO3-(aq) + 2H+(aq) + H2(g) Conditions: [0.15 atm] [0.18 atm] [0.1 M] [0.1 M] [0.67 atm] Find the cell potential, E Report your answer in 2 decimal places. Do not include the unit
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter17: Electrochemistry And Its Applications
Section: Chapter Questions
Problem 38QRT
Related questions
Question
Given the following reactions:
Anode: NO3- + 2H+ + e- --> NO2 + H2O
Cathode: 2H+ + 2e- --> H2
Redox: 2NO2(g) + 2 H2O (l) --> 2NO3-(aq) + 2H+(aq) + H2(g)
Conditions: [0.15 atm] [0.18 atm] [0.1 M] [0.1 M] [0.67 atm]
Find the cell potential, E
Report your answer in 2 decimal places. Do not include the unit
![Table 7.2 Standard potentials at 298 K. (a) In electrochemical order
Reduction half reaction
E"/V
Reduction half-reaction
EIV
Strongly oxidizing
Cu" +eCu
+0.16
+3.0
Sn" + 2e
Sn
H,XeO, + 2H" +2e→ XeO, + 3H,O
F+2e2F"
0,+ 2H" + 2-0, + H,0
S,여 +2e→2s0어
Ag +e Ag
Co" +eCo"
+0.15
AgBr +e Ag + Br
Ti" +eTi"
2H + 2eH,
+2.87
+0.07
+2.07
0.00
+2.05
a, by defin
+1.98
Fe" + 3Fe
-0.04
0,+H,0+ 2e° -> HO; +Of"
Fb + 2e Pb
+L8I
-0.08
H,O, + 2H" +2e 21,0
Au' +eAu
Pb + 2e Pb
2HCIO + 2H' + 2e a, + 211,0
Cet +eCe
21IBrO+ 211 + 2e Br,+ 2H0
+1.78
-0.13
In +eIn
Sn+2e Sn
Agl +e Ag+
Ni" +2e Ni
Co" + 2eCo
In" + eIn
+1.69
-0.14
+1.67
-0.14
+1.63
-0.15
+1.61
-0.23
+1.60
-0.28
Mno, + BH" + Se Mn" + 4H,0
Mn" +eMn
Au" +3eAu
+1.51
-0.34
+1.51
1 +e TI
-0.34
+1.40
PESO, + 2e Pb + So
-0.36
+1.36
-0.37
Cr,0 +14H* +6e →2Cr" +7H,0
0, +H,0 + 2e" -→O, + 20H
O, +4H' + 4e 2H,0
Co, + 2H" + 2e-do; +H,0
MnO, + 4H + 2e - Ma" + 21,0
Br, + 2e 2Br
Pu" +e Pu"
+1.33
C +2eCd
-0.40
+1.24
Ine In
-0.40
+1.23
-041
Fe+ 2eFe
In + 2e In
S+2es
+1.23
-0.44
+1.23
-0.44
+1.09
-0.48
+0.97
In" +e In
-0.49
NO, +4H + 3e -NO+ 2H,0
2Hg" + 2e Hg
ClO +H,0+2e Cr + 20H
Hg" + 2e - Hg
NO, + 2H +e- NO, + H,0
+0.96
-0.61
+0.92
C+ Cr
-0.74
+0.89
Za" + 2 Zn
-0.76
+0.86
Ca(OH), + 2e-Cd + 20H
+0.80
21,0+ 2e-1, + 2011
-0.83
Ag+eAg
Hg" + 2e 21ig
Fe" +eFe*
BrO + H,0+ 2e Br + 20H
Hg,SO, + 2e -2Hg + SO?
Mno + 2H,0+ 2e"→MNO, + 40H
MnO, +e Mno
1+2e 21
+0.80
C*+2eCr
-0.91
+0.79
Mn +2e Mn
-L.18
+0.77
V+ 2eV
-1.19
+0.76
-1.63
+0.62
AP + 3e A
-1.66
+0.60
U+3e U
-1.79
+0.56
Se+3eS
-2.09
Mg* + 2e Mg
Ce" + 3eCe
+0.54
-236
+0.52
-2.48
5+ 2e31
NIOOH +H,0+e→ Ni(OH), + OH
Ag,CrO, + 2e 2Ag + CrO
O,+ 2H,0+ de-4OH
do, +1,0+2e CIO; + 20H
(Fe{CN),* +e" → [Fe(CN),J*
Cu + 2eCu
La" + 3ela
Na* +e Na
Ca +2eCa
Se + 2e Sr
+0.53
-2.52
+0.49
-271
+0.45
-2.87
+0.40
-2.89
+0.36
Ba" + 2e+ Ba
-2.91
+0.36
Ra+2eRa
-2.92
+0.34
-2.92
HgCI, + 2e + 2Hg + 20
Aga+e Ag + a
Bi +e Bi
40.27
Rb +e Rb
-2.93
+0.22
K*+eK
-2.93
+0.20
L +eLi
-3.05](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F948439f7-46e9-415a-a4e4-eb6a200002a9%2F44e82eeb-2c8f-4e86-9a9a-c051ba90f9fb%2Fnzq3ur9_processed.png&w=3840&q=75)
Transcribed Image Text:Table 7.2 Standard potentials at 298 K. (a) In electrochemical order
Reduction half reaction
E"/V
Reduction half-reaction
EIV
Strongly oxidizing
Cu" +eCu
+0.16
+3.0
Sn" + 2e
Sn
H,XeO, + 2H" +2e→ XeO, + 3H,O
F+2e2F"
0,+ 2H" + 2-0, + H,0
S,여 +2e→2s0어
Ag +e Ag
Co" +eCo"
+0.15
AgBr +e Ag + Br
Ti" +eTi"
2H + 2eH,
+2.87
+0.07
+2.07
0.00
+2.05
a, by defin
+1.98
Fe" + 3Fe
-0.04
0,+H,0+ 2e° -> HO; +Of"
Fb + 2e Pb
+L8I
-0.08
H,O, + 2H" +2e 21,0
Au' +eAu
Pb + 2e Pb
2HCIO + 2H' + 2e a, + 211,0
Cet +eCe
21IBrO+ 211 + 2e Br,+ 2H0
+1.78
-0.13
In +eIn
Sn+2e Sn
Agl +e Ag+
Ni" +2e Ni
Co" + 2eCo
In" + eIn
+1.69
-0.14
+1.67
-0.14
+1.63
-0.15
+1.61
-0.23
+1.60
-0.28
Mno, + BH" + Se Mn" + 4H,0
Mn" +eMn
Au" +3eAu
+1.51
-0.34
+1.51
1 +e TI
-0.34
+1.40
PESO, + 2e Pb + So
-0.36
+1.36
-0.37
Cr,0 +14H* +6e →2Cr" +7H,0
0, +H,0 + 2e" -→O, + 20H
O, +4H' + 4e 2H,0
Co, + 2H" + 2e-do; +H,0
MnO, + 4H + 2e - Ma" + 21,0
Br, + 2e 2Br
Pu" +e Pu"
+1.33
C +2eCd
-0.40
+1.24
Ine In
-0.40
+1.23
-041
Fe+ 2eFe
In + 2e In
S+2es
+1.23
-0.44
+1.23
-0.44
+1.09
-0.48
+0.97
In" +e In
-0.49
NO, +4H + 3e -NO+ 2H,0
2Hg" + 2e Hg
ClO +H,0+2e Cr + 20H
Hg" + 2e - Hg
NO, + 2H +e- NO, + H,0
+0.96
-0.61
+0.92
C+ Cr
-0.74
+0.89
Za" + 2 Zn
-0.76
+0.86
Ca(OH), + 2e-Cd + 20H
+0.80
21,0+ 2e-1, + 2011
-0.83
Ag+eAg
Hg" + 2e 21ig
Fe" +eFe*
BrO + H,0+ 2e Br + 20H
Hg,SO, + 2e -2Hg + SO?
Mno + 2H,0+ 2e"→MNO, + 40H
MnO, +e Mno
1+2e 21
+0.80
C*+2eCr
-0.91
+0.79
Mn +2e Mn
-L.18
+0.77
V+ 2eV
-1.19
+0.76
-1.63
+0.62
AP + 3e A
-1.66
+0.60
U+3e U
-1.79
+0.56
Se+3eS
-2.09
Mg* + 2e Mg
Ce" + 3eCe
+0.54
-236
+0.52
-2.48
5+ 2e31
NIOOH +H,0+e→ Ni(OH), + OH
Ag,CrO, + 2e 2Ag + CrO
O,+ 2H,0+ de-4OH
do, +1,0+2e CIO; + 20H
(Fe{CN),* +e" → [Fe(CN),J*
Cu + 2eCu
La" + 3ela
Na* +e Na
Ca +2eCa
Se + 2e Sr
+0.53
-2.52
+0.49
-271
+0.45
-2.87
+0.40
-2.89
+0.36
Ba" + 2e+ Ba
-2.91
+0.36
Ra+2eRa
-2.92
+0.34
-2.92
HgCI, + 2e + 2Hg + 20
Aga+e Ag + a
Bi +e Bi
40.27
Rb +e Rb
-2.93
+0.22
K*+eK
-2.93
+0.20
L +eLi
-3.05
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